You could pass the string through a decimal formatter to get the underlying number, and then back again through the formatter to get a formatted string:
let amount = "123,456,789"
let formatter = NumberFormatter()
formatter.numberStyle = .decimal
formatter.maximumFractionDigits = 2
formatter.minimumFractionDigits = 2
let number = formatter.number(from: amount)
let newAmountString = formatter.string(from: number!) //"123,456,789.00"
(You should check that number is not nil
before force unwrapping it, with if let
or guard
)
You could wrap this in a function:
func zeroPadding(toString: String) -> String? {
let formatter = NumberFormatter()
formatter.numberStyle = .decimal
formatter.maximumFractionDigits = 2
formatter.minimumFractionDigits = 2
guard let number = formatter.number(from: toString) else {
return nil
}
return formatter.string(from: number)
}
Here are some test cases:
zeroPadding(toString: "123,456,789") //"123,456,789.00"
zeroPadding(toString: "123,456,789.0") //"123,456,789.00"
zeroPadding(toString: "123,456,789.10") //"123,456,789.10"
zeroPadding(toString: "123,456,789.123") //"123,456,789.12"
zeroPadding(toString: "123.4567") //"123.46"
zeroPadding(toString: "Price: 1€ for a ") //nil
Or define it as an extension on String:
extension String {
func withZeroPadding() -> String? {
let formatter = NumberFormatter()
formatter.numberStyle = .decimal
formatter.maximumFractionDigits = 2
formatter.minimumFractionDigits = 2
guard let number = formatter.number(from: self) else {
return nil
}
return formatter.string(from: number)
}
}
And use it like this:
"123.4.4.5".withZeroPadding() //nil
"12.".withZeroPadding() //"12.00"
"123,456,789".withZeroPadding() //"123,456,789.00"