Find text javascript

Question

I Have string random length

Ex:

 sadsadsadsad(323213)dfsssds

 sadsadsadsad(321)dfsssds

How can I find the values in brackets?.

Value random length

Thank for reading

What have you tried in order to find them? Have you tried [tag:regex]? — Luca Kiebel, Sep 10 '18 at 15:39
Possible duplicate of [Regular Expression to get a string between parentheses in Javascript](https://stackoverflow.com/questions/17779744/regular-expression-to-get-a-string-between-parentheses-in-javascript) — l2aelba, Sep 10 '18 at 15:41
You may want to accept the Duplicate, the answers will give you everything you need. — Luca Kiebel, Sep 10 '18 at 15:44

hong4rc · Answer 1 · 2018-09-10T16:18:19.943

1

Try regex /\(.*\)/

function getValue(s) {
    var strs = s.match(/\(.*?\)/g);
    if (strs == null) {
        return '';
    }
    return strs.map(str=>str.replace(/[()]/g, ''));
    //return strs.join(' ,').replace(/[()]/g, '')
}



console.log(getValue('sadsadsadsad(323213)dfsssds(abc)'));
console.log(getValue('sadsad(_d_)sadsad(321)dfsssds'));
console.log(getValue('sadsad(33)sadsad(321dfsssds'));

edited Sep 10 '18 at 16:18

answered Sep 10 '18 at 15:44

hong4rc

3,999
4
21
40

Thank for help, adsdadsdas(123)adadadad(123431) I need find (123) and (123431) how to? – Lightrain125 Sep 10 '18 at 15:59
@Lightrain125 `adsdadsdas(123)adadadad(123431)` return `123123431` ? – hong4rc Sep 10 '18 at 16:08
return 123,123123431 – Lightrain125 Sep 10 '18 at 16:14
Your mean is return Array or return string with `,` ? – hong4rc Sep 10 '18 at 16:15

Ehsan · Accepted Answer · 2018-09-10T16:59:17.270

1

Try This:

var str =  'sadsadsadsad(321)dfss888s(120)ds';

str.match(/\(\d+\)/g).map ( value => { console.log( value.replace(/[)(]/g, '') ) } );

edited Sep 10 '18 at 16:59

answered Sep 10 '18 at 15:58

Ehsan

12,655
3
25
44

score 0 · Answer 3 · answered Sep 10 '18 at 15:41

0

You can use lastIndexOf and substring

var text = "sadsadsadsad(323213)dfsssds";
var newText = text.substring(text.lastIndexOf("(") + 1, text.lastIndexOf(")"));

console.log(newText)

answered Sep 10 '18 at 15:41

michaelitoh

2,317
14
26

Thank for help, adsdadsdas(123)adadadad(123431) I need find (123) and (123431) how to? – Lightrain125 Sep 10 '18 at 15:50

score 0 · Answer 4 · answered Sep 10 '18 at 15:41

0

You can use indexOf and substring

let str = 'sadsadsadsad(321)dfsssds';

let getFirstIndex = str.indexOf('(');
let getSecondIndex = str.indexOf(')');

let subStr = str.substring(getFirstIndex + 1, getSecondIndex);
console.log(subStr)

answered Sep 10 '18 at 15:41

brk

48,835
10
56
78

Thank for help, adsdadsdas(123)adadadad(123431) I need find (123) and (123431) how to? – Lightrain125 Sep 10 '18 at 15:51

score 0 · Answer 5 · answered Sep 10 '18 at 15:44

0

var str = "sadsadsadsad(323213)dfsssds"; 
var val= str.match(/\((.*?)\)/);
if (val) {
    console.log("found");
 }

You can use Regex

var str = "sadsadsadsad(323213)dfsssds"; 
var val= str.match(/\((.*?)\)/);
if (val) {
    console.log("found");
 }

answered Sep 10 '18 at 15:44

Yuri

2,820
4
28
40

Thank for help, adsdadsdas(123)adadadad(123431) I need find (123) and (123431) how to? – Lightrain125 Sep 10 '18 at 15:47
Please refer to this article: https://stackoverflow.com/questions/6323417/how-do-i-retrieve-all-matches-for-a-regular-expression-in-javascript – Yuri Sep 10 '18 at 15:50

score 0 · Answer 6 · answered Sep 10 '18 at 15:47

Try by using the following code it will helps you if you have remove nested Parentheses example "a(bcdefghijkl(mno)p)q"

function removeParentheses(s) {
    let openPatterns = [];
    for(let i=0; i < s.length; i++){

        if(s[i] == '('){
            openPatterns.push(i);
        }

        if(s[i] == ')'){
            const lastIndexOpen = openPatterns.pop();
            const originalTxt = s.slice(lastIndexOpen ,i+1);
            //here you have the raw text      
            const rawText = s.slice(lastIndexOpen+1,i);
            //this code works to remove the parentesis 
            //s= s.replace(originalTxt, reverseTxt);
            //i-=2;
        }
    }
    return rawText;    
}

score 0 · Answer 7 · answered Sep 10 '18 at 16:39

You could catch the group within () using replace(), and passing it to a callback function that push it into an array.

var str = 'sadsadsadsad(323213)dfsssds(1234)dfsssds(4567)dfsssds(abcf)';

var arr = [];

str.replace(/\(([a-z0-9]*)\)+/gi, (a,b)=>arr.push(b));

console.log(arr);

Find text javascript

7 Answers7

Linked