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I am trying to get the response from the ajax request below. when i remove .sucess{}, the data table is filtered with the response correctly. But i want to get the data(response) and pass it to variable results.

How do i get this done please?

$('#statusFilter').on('change', function () {
    var results = false;
    var filter_value = $(this).val();
    dtListUsers.ajax.
        url('/user/json/' + filter_value)
        .load()
        .sucess: function(data) {
        results = data;
    }
    ;
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<table id="dtListUsers" class="table">
        <thead>
            <tr>
                <th>Name</th>
            </tr>
        </thead>
        <tbody>
        </tbody>
    </table>
Mohammad Ali Rony
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Michael Anaman
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0 Answers0