How get all values in a column using PHP?

Question

I've been searching for this everywhere, but still can't find a solution: How do I get all the values from a mySQL column and store them in an array?

For eg: Table Name: Customers Column names: ID, Name # of rows: 5

I want to get an array of all the 5 names in this table. How do I go about doing that? I am using PHP, and I was trying to just:

SELECT names FROM Customers

and then use the

mysql_fetch_array

PHP function to store those values in an array.

Answer 1

Here is a simple way to do this using either PDO or mysqli

$stmt = $pdo->prepare("SELECT Column FROM foo");
// careful, without a LIMIT this can take long if your table is huge
$stmt->execute();
$array = $stmt->fetchAll(PDO::FETCH_COLUMN);
print_r($array);

or, using mysqli

$stmt = $mysqli->prepare("SELECT Column FROM foo");
$stmt->execute();
$array = [];
foreach ($stmt->get_result() as $row)
{
    $array[] = $row['column'];
}
print_r($array);

---

Array
(
    [0] => 7960
    [1] => 7972
    [2] => 8028
    [3] => 8082
    [4] => 8233
)

Answer 2

Note that this answer is outdated! The mysql extension is no longer available out of the box as of PHP7. If you want to use the old mysql functions in PHP7, you will have to compile ext/mysql from PECL. See the other answers for more current solutions.

---

This would work, see more documentation here : http://php.net/manual/en/function.mysql-fetch-array.php

$result = mysql_query("SELECT names FROM Customers");
$storeArray = Array();
while ($row = mysql_fetch_array($result, MYSQL_ASSOC)) {
    $storeArray[] =  $row['names'];  
}
// now $storeArray will have all the names.

Answer 3

I would use a mysqli connection to connect to the database. Here is an example:

$connection = new mysqli("127.0.0.1", "username", "password", "database_name", 3306);

The next step is to select the information. In your case I would do:

$query = $connection->query("SELECT `names` FROM `Customers`;");

And finally we make an array from all these names by typing:

$array = Array();
while($result = $query->fetch_assoc()){
    $array[] = $result['names'];
}

print_r($array);

So what I've done in this code: I selected all names from the table using a mysql query. Next I use a while loop to check if the $query has a next value. If so the while loop continues and adds that value to the array '$array'. Else the loop stops. And finally I print the array using the 'print_r' method so you can see it all works. I hope this was helpful.

Answer 4

Since mysql_* are deprecated, so here is the solution using mysqli.

$mysqli = new mysqli('host', 'username', 'password', 'database');
if($mysqli->connect_errno>0)
{
  die("Connection to MySQL-server failed!"); 
}
$resultArr = array();//to store results
//to execute query
$executingFetchQuery = $mysqli->query("SELECT `name` FROM customers WHERE 1");
if($executingFetchQuery)
{
   while($arr = $executingFetchQuery->fetch_assoc())
   {
        $resultArr[] = $arr['name'];//storing values into an array
   }
}
print_r($resultArr);//print the rows returned by query, containing specified columns

There is another way to do this using PDO

  $db = new PDO('mysql:host=host_name;dbname=db_name', 'username', 'password'); //to establish a connection
  //to fetch records
  $fetchD = $db->prepare("SELECT `name` FROM customers WHERE 1");
  $fetchD->execute();//executing the query
  $resultArr = array();//to store results
  while($row = $fetchD->fetch())
  {
     $resultArr[] = $row['name'];
  }
  print_r($resultArr);

Answer 5

PHP 5 >= 5.5.0, PHP 7

Use array_column on the result array

$column = array_column($result, 'names');

Answer 6

How to put MySQL functions back into PHP 7
Step 1

First get the mysql extension source which was removed in March:

https://github.com/php/php-src/tree/PRE_PHP7_EREG_MYSQL_REMOVALS/ext/mysql

Step 2

Then edit your php.ini

Somewhere either in the “Extensions” section or “MySQL” section, simply add this line:

extension = /usr/local/lib/php/extensions/no-debug-non-zts-20141001/mysql.so

Step 3

Restart PHP and mysql_* functions should now be working again.

Step 4

Turn off all deprecated warnings including them from mysql_*:

error_reporting(E_ALL ^ E_DEPRECATED);

Now Below Code Help You :

$result = mysql_query("SELECT names FROM Customers");
$Data= Array();
while ($row = mysql_fetch_array($result, MYSQL_ASSOC)) 
{
        $Data[] =  $row['names'];  
}

You can also get all values in column using mysql_fetch_assoc

$result = mysql_query("SELECT names FROM Customers");
    $Data= Array();
    while ($row = mysql_fetch_assoc($result)) 
    {
            $Data[] =  $row['names'];  
    }

This extension was deprecated in PHP 5.5.0, and it was removed in PHP 7.0.0. Instead, the MySQLi or PDO_MySQL extension should be used.

Reference

---

YOU CAN USE MYSQLI ALTERNATIVE OF MYSQL EASY WAY

---

*

<?php
$con=mysqli_connect("localhost","my_user","my_password","my_db");
// Check connection
if (mysqli_connect_errno())
  {
  echo "Failed to connect to MySQL: " . mysqli_connect_error();
  }

$sql="SELECT Lastname,Age FROM Persons ORDER BY Lastname";
$result=mysqli_query($con,$sql);

// Numeric array
$row=mysqli_fetch_array($result,MYSQLI_NUM);
printf ("%s (%s)\n",$row[0],$row[1]);

// Associative array
$row=mysqli_fetch_array($result,MYSQLI_ASSOC);
printf ("%s (%s)\n",$row["Lastname"],$row["Age"]);

// Free result set
mysqli_free_result($result);

mysqli_close($con);
?> 

Answer 7

First things is this is only for advanced developers persons Who all are now beginner to php dont use this function if you are using the huge project in core php use this function

function displayAllRecords($serverName, $userName, $password, $databaseName,$sqlQuery='')
{
    $databaseConnectionQuery =  mysqli_connect($serverName, $userName, $password, $databaseName);
    if($databaseConnectionQuery === false)
    {
        die("ERROR: Could not connect. " . mysqli_connect_error());
        return false;
    }

    $resultQuery = mysqli_query($databaseConnectionQuery,$sqlQuery);
    $fetchFields = mysqli_fetch_fields($resultQuery);
    $fetchValues = mysqli_fetch_fields($resultQuery);

    if (mysqli_num_rows($resultQuery) > 0) 
    {           

        echo "<table class='table'>";
        echo "<tr>";
        foreach ($fetchFields as $fetchedField)
         {          
            echo "<td>";
            echo "<b>" . $fetchedField->name . "<b></a>";
            echo "</td>";
        }       
        echo "</tr>";
        while($totalRows = mysqli_fetch_array($resultQuery)) 
        {           
            echo "<tr>";                                
            for($eachRecord = 0; $eachRecord < count($fetchValues);$eachRecord++)
            {           
                echo "<td>";
                echo $totalRows[$eachRecord];
                echo "</td>";               
            }
            echo "<td><a href=''><button>Edit</button></a></td>";
            echo "<td><a href=''><button>Delete</button></a></td>";
            echo "</tr>";           
        } 
        echo "</table>";        

    } 
    else
    {
      echo "No Records Found in";
    }
}

All set now Pass the arguments as For Example

$queryStatment = "SELECT * From USERS "; $testing = displayAllRecords('localhost','root','root@123','email',$queryStatment); echo $testing;

Here

localhost indicates Name of the host,

root indicates the username for database

root@123 indicates the password for the database

$queryStatment for generating Query

hope it helps