Removing word from grep output

Question

I have the following bash command:

cat setup.py | grep name=`

This returns the line

name='SOME_PROJECTNAME',

How would I pipe this output from grep to just retrieve SOME_PROJECTNAME?

I have tried

cat setup.py | grep name= | tr -d 'name=','

but this removes characters in SOME_PROJECTNAME.

And/or https://stackoverflow.com/questions/9553715/how-to-get-value-of-variable-config-in-bash, https://stackoverflow.com/questions/15148796/get-string-after-character, https://stackoverflow.com/questions/10358547/how-to-grep-for-contents-after-pattern — Benjamin W., Sep 13 '18 at 17:38
See also https://stackoverflow.com/questions/11710552/useless-use-of-cat — tripleee, Sep 13 '18 at 17:57

score 2 · Accepted Answer · answered Sep 13 '18 at 17:38

2

Use grep lookahead.

$ grep -oP "(?<=name=').*(?=')" setup.py

answered Sep 13 '18 at 17:38

iamauser

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Note that `grep` manual says about `-P`: _This is highly experimental and grep -P may warn of unimplemented features_. – Jérôme Pouiller Sep 15 '18 at 07:38

Jack · Answer 2 · 2018-09-13T17:52:33.007

0

#bad cat setup.py | grep name= | cut -d= -f2-
cat setup.py | grep name= | cut -d' -f2

edited Sep 13 '18 at 17:52

answered Sep 13 '18 at 17:33

Jack

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score 0 · Answer 3 · edited Sep 13 '18 at 19:29

0

Sed may be helpful here.

 sed -ne "s/name='\(.*\)'/\1/p" setup.py

The option -n makes sed not print lines by default. Then we replace the entire property line (name='SOME_PROJECTNAME') with the value only (SOME_PROJECTNAME). The p flag in the s/// command makes sed print the line only if the replacement its executed. So, the only line to be printed are the ones where the replacement was done, with the replaced value.

edited Sep 13 '18 at 19:29

brandizzi

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answered Sep 13 '18 at 17:35

Jérôme Pouiller

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Wouldn't that return `SOME_PROJECTNAME'` (with single quote)? – Benjamin W. Sep 13 '18 at 17:38

Removing word from grep output

3 Answers3