Python sorting numbers on last digit?

Question

My question is i have inp=[1,52,234,65,87,57,96,0,3] and output should be output=[0,1,52,3,234,65,96,87,57]. if the last digit is the same you leave them in same order as they are on input.increasing.

inp=[1,52,234,65,87,57,96,0,3]
output=[0,1,52,3,234,65,96,87,57]

how you sort integers on last digit?

Possible duplicate of [Sort array of objects by string property value in JavaScript](https://stackoverflow.com/questions/1129216/sort-array-of-objects-by-string-property-value-in-javascript) — ThoFin, Sep 15 '18 at 04:47

score 5 · Answer 1 · answered Sep 14 '18 at 22:33

5

You can sort using a key function that calculates n%10:

sorted(inp, key=lambda n: n%10)

or

sorted(inp, key=(10).__rmod__)

answered Sep 14 '18 at 22:33

Patrick Haugh

59,226
13
88
96

score 1 · Answer 2 · answered Sep 14 '18 at 22:33

1

The last digit of a number is the remainder of division by 10:

sorted(inp, key=lambda x: x % 10)
#[0, 1, 52, 3, 234, 65, 96, 87, 57]

answered Sep 14 '18 at 22:33

DYZ

55,249
10
64
93

N Chauhan · Answer 3 · 2018-09-14T22:34:41.123

0

You can use the sorted() built in with the keyword argument key:

sort = sorted(inp,
              key=lambda x: str(x)[-1])

This takes the value, converts it to a string to get the -1 index from it, then that value is able to be compared and sorted. You don't need to cast it back into an integer.

edited Sep 14 '18 at 22:34

answered Sep 14 '18 at 22:33

N Chauhan

3,407
2
7
21

Python sorting numbers on last digit?

3 Answers3