0

I am trying to read a few lines from a file and store the ASCII value of each character read as I go line by line. My input looks like this:

input

Here is what my code originally looked like and what it produced:

char buf3[256], buf5[256], buf6[256], buf7[256], buf4[256], buf9[256];
    fscanf(fp, "%[^\n]", buf3);
while (!feof(fp)) {
    fscanf(fp, "%s %s %s %s %s", buf4, buf5, buf6, buf7, buf9);
    printf("\n%c %c %c %c %c", *buf4, *buf5, *buf6, *buf7, *buf9);
}

result

I thought printing out %c would give me the ASCII value. Is there a way to convert these values?

phuclv
  • 37,963
  • 15
  • 156
  • 475
level1
  • 87
  • 6
  • You need to use `%d` to print out the ASCII value of a character - example: `printf("%d",buf5[0]);` + learn how to access each character of a string. – Gaurav Sep 16 '18 at 00:23
  • `*buf4, *buf5, *buf6, *buf7, *buf` will print the first character in each array. (the `%d` conversion is correct to print the ASCII value -- to convert to decimal value you would subtract `'0'` from the character value) You will want to look at [**Why is while ( !feof (file) ) always wrong?**](http://stackoverflow.com/questions/5431941/why-is-while-feof-file-always-wrong). – David C. Rankin Sep 16 '18 at 00:24
  • you should copy and paste the input and output here. Putting them in images will prevent people from trying the code – phuclv Sep 16 '18 at 01:00

2 Answers2

0

Let's suppose your input 011R0 is stored in array buf then to print ASCII value of each character, you'll have to access each character and print it as if you are printing an integer:

  int i;
  while(buf[i])
   {
       printf("%d\n",buf[i]);
       ++i;
   }

By using indices [i] one can access each character if the string. Besides that have a look at this: Why is “while ( !feof (file) )” always wrong?

Gaurav
  • 1,570
  • 5
  • 17
-1

I thought printing out %c would give me the ASCII value ? No, the format specifier %c prints equivalents char value, since buf4, buf5..etc are char array, so when you prints *buf5 it prints first char of array & if you print ascii value of that, you have to subtract it from 48(ASCII value of 0) if *buf contains digits(0 - 9). For e.g 

printf("%d\n",(*buf4)  - 48);

Or

printf("%d\n",(*buf4)  - '0');

Also for this particular case its wstage of stack memory to declare five char array like buf3,buf4..buf9. you can use just one char array & do the operation. For e.g

int index = 0 ;
char buf[20]; /* lets say each word of file are length of 20 char, you can change it */
while (fscanf(fp,"%s",buf) != EOF) {
        while(buf[index] != '\0') {     
                if(buf[index] >= '0' && buf[index] <= '9') { /*or use isdigit() */
                        printf("%d",buf[index] - 48);
                }
                else { /* apart from 0,1,...9 */
                        printf("%d",buf[index]);
                }
                index++;
        }
        printf(" ");
        index = 0;
}

Also read why its wrong to use feof() here

Achal
  • 11,821
  • 2
  • 15
  • 37
  • I've edited my answer. Down voter please have a look if any other issues or retract Dv. – Achal Sep 16 '18 at 01:24