How to generate random word from a set of characters in python

Question

I am looking to generate a random word list from a set of characters in python. Problem here:-

It is Generating like:- aaaaaa aaaaab aaaaac ...... So on

I want to add random function so it generate same length with randomization of alphabets it has like:- a15bef f45acd 9bbac0 ...... So on

Look With same length but random.

How to add random function to it?

#Code
import itertools

chrs = 'abcdef0123456789' # Change your required characters here
n = 6 # Change your word length here

for xs in itertools.product(chrs, repeat=n):
   print(''.join(xs))

please help me to solve it.

Raj - asked & answered here: https://stackoverflow.com/questions/2823316/generate-a-random-letter-in-python — keithpjolley, Sep 16 '18 at 11:37
Possible duplicate of [Generate a random letter in Python](https://stackoverflow.com/questions/2823316/generate-a-random-letter-in-python) — Vineeth Sai, Sep 16 '18 at 11:38
Possible duplicate of https://stackoverflow.com/questions/2257441/random-string-generation-with-upper-case-letters-and-digits-in-python — Sruthi, Sep 16 '18 at 11:39

score 2 · Accepted Answer · answered Sep 16 '18 at 11:50

2

itertools.product will generate all the possible values. Instead, what you want is to pick n random characters from chrs and concatenate them:

import random

chrs = 'abcdef0123456789' # Change your required characters here
n = 6 # Change your word length here

print(''.join(random.choices(chrs, k=5)))

answered Sep 16 '18 at 11:50

Maxime Chéramy

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Very good suggested and its working without itertools and consume less memory means faster work. – Raj Tekken Sep 16 '18 at 13:29

Peyman.H · Answer 2 · 2018-09-16T11:46:59.517

1

You can do it by random.choice:

import random
chrs = 'abcdef0123456789'
n = 6
result = ''.join(random.choice(chrs) for _ in range(n))

edited Sep 16 '18 at 11:46

answered Sep 16 '18 at 11:39

Peyman.H

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Alex · Answer 3 · 2018-09-16T11:44:43.823

0

''.join(random.choice(‘abcdef0123456789’) for _ in range(N))

A cryptographical more secure option is here, below example will generate random string using all undercase alphabets and digits

''.join(random.SystemRandom().choice(string.ascii_uppercase + string.digits) for _ in range(N))

edited Sep 16 '18 at 11:44

answered Sep 16 '18 at 11:41

Alex

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it says - NameError: name 'string' is not defined – Raj Tekken Sep 16 '18 at 13:42
We import string, a module that contains sequences of common ASCII characters, and random, a module that deals with random generation – Alex Sep 16 '18 at 16:18

score 0 · Answer 4 · edited Apr 09 '19 at 05:32

I use something like this

import random
def generateAWord (length):
    i = 0
    result = ""
    while i < length:
        letter = chr(33 + int(93 * random.random()))
        result += letter
        i +=1
    return result

33 in inside chr is the first ascii decimal that you want( 33 represent {!}). random.random() return the next random floating point number in the range [0.0, 1.0] so it times that 0.0 - 1.0 by 93 for example 0.1732*93 will result 16,1076 (and it cast that to int, so it will end as 16). So 93 represent the max result from the starting ascii decimal that you want(in this case 33) until the max ascii decimal that you want(in this case 33+93 is 126 which is {~} in ascii decimal).

Then chr will convert that result to char.

How to generate random word from a set of characters in python

4 Answers4