PHP Getting a value form a form in POST that has values from a PHP script

Question

I created some PHP code to get values from a database and show them as an option in a form I created using HTML. Now I want to be able to select one of those options and then process that in POST. But it gives me an error that my index is undefined when I try to get that value in POST. So I guess my question is, is getting this value possible? If so, how would I accomplish this?

Here is my code:

<form method="post" action="dayzconfigedit.php">
<select name="item1">;
    <?php
        //Display the Items from the database in a dropdown menu
        $sql = "SELECT item_id FROM `all_items`";
        $result = $conn->query($sql);
        for($x = 0; $x < $result->num_rows; $x++) {
            $row = $result->fetch_assoc();
            echo "<option value=\"{$row["item_id"]}\">{$row["item_id"]}</option>";
        }
    ?>
</select>
</form>

Then I try to get value in POST:

if ( $_SERVER['REQUEST_METHOD'] == 'POST' ) {
    //Grab Selected Items from Form
    $item1 = "$_POST[item1]";
}

Thanks in advance!

I skimmed through the post that supposedly answers my question but I still can't solve this issue because I don't know why the index is undefined in the POST array.

Yes, I added the form to the post. – Gavin Sep 16 '18 at 18:19 — Gavin, Sep 16 '18 at 18:19

Simon R · Accepted Answer · 2018-09-16T18:22:45.447

1

You need to grab item 1 like this;

if ( $_SERVER['REQUEST_METHOD'] == 'POST' ) {
    //Grab Selected Items from Form
    $item1 = ! empty($_POST['item1']) ? $_POST['item1'] : null;
}

Also, please update where you echo the option to be;

echo"<option value=\"{$row["item_id"]}\">{$row["item_id"]}</option>";

edited Sep 16 '18 at 18:22

answered Sep 16 '18 at 18:08

Simon R

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This removed the error but I still am not getting the value from my form. – Gavin Sep 16 '18 at 18:13
I've updated my answer – Simon R Sep 16 '18 at 18:22
Simon, I thought this would fix it but sadly I'm still receiving the same error. – Gavin Sep 16 '18 at 18:26
What results do you get if you add die(var_dump($_POST)); straight after if ( $_SERVER['REQUEST_METHOD'] == 'POST' ) { – Simon R Sep 16 '18 at 18:32
It tells me that the array is empty. – Gavin Sep 16 '18 at 18:35
I figured it out! It was because I had two forms on the page. I needed to move the submit button into the form with my select tag in it. Thanks for the help! – Gavin Sep 16 '18 at 18:37

score 0 · Answer 2 · answered Sep 16 '18 at 18:08

0

You may either missed to specify method="post" in form tag .. or you missed to specify the name of the field <select> tag like <select name="item1">.

Now you can access the submitted value in $_POST["item1"]

answered Sep 16 '18 at 18:08

Veshraj Joshi

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Yah, I missed that. But even after adding that into my form it still throws the same error. – Gavin Sep 16 '18 at 18:13
could you please show the html form in question – Veshraj Joshi Sep 16 '18 at 18:14
Yes, I added the form to the inital post. – Gavin Sep 16 '18 at 18:18

score 0 · Answer 3 · answered Sep 16 '18 at 18:14

0

I am not well versed in PHP but i think your code should read

if ( $_SERVER['REQUEST_METHOD'] == 'POST' ) {
    //Grab Selected Items from Form
    $item1 = $_POST["item1"]; //Take note of this line
}

answered Sep 16 '18 at 18:14

Kudzai Mutsvairo

95
1
9

Thanks for the comment! I tried this change but it made no difference. I still received the error. – Gavin Sep 16 '18 at 18:20
Would you mind sharing the code for the form – Kudzai Mutsvairo Sep 16 '18 at 18:37
Thanks for the reply but I already solved my problem. I had to move my submit button as it was in the wrong form tag. Thanks for the help! – Gavin Sep 16 '18 at 18:39
Alright congrats – Kudzai Mutsvairo Sep 16 '18 at 19:10

PHP Getting a value form a form in POST that has values from a PHP script

3 Answers3