Best way to concatenate List of String objects?

Question

What is the best way to concatenate a list of String objects? I am thinking of doing this way:

List<String> sList = new ArrayList<String>();

// add elements

if (sList != null)
{
    String listString = sList.toString();
    listString = listString.subString(1, listString.length() - 1);
}

I somehow found this to be neater than using the StringBuilder/StringBuffer approach.

Any thoughts/comments?

Answer 1

Use one of the the StringUtils.join methods in Apache Commons Lang.

import org.apache.commons.lang3.StringUtils;

String result = StringUtils.join(list, ", ");

If you are fortunate enough to be using Java 8, then it's even easier...just use String.join

String result = String.join(", ", list);

Answer 2

Using Java 8+

String str = list.stream().collect(Collectors.joining())

or even

String str = String.join("", list);

Answer 3

Your approach is dependent on Java's ArrayList#toString() implementation.

While the implementation is documented in the Java API and very unlikely to change, there's a chance it could. It's far more reliable to implement this yourself (loops, StringBuilders, recursion whatever you like better).

Sure this approach may seem "neater" or more "too sweet" or "money" but it is, in my opinion, a worse approach.

Answer 4

A variation on codefin's answer

public static String concatStringsWSep(Iterable<String> strings, String separator) {
    StringBuilder sb = new StringBuilder();
    String sep = "";
    for(String s: strings) {
        sb.append(sep).append(s);
        sep = separator;
    }
    return sb.toString();                           
}

Answer 5

If you are developing for Android, there is TextUtils.join provided by the SDK.

Answer 6

This is the most elegant and clean way I've found so far:

list.stream().collect(Collectors.joining(delimiter));

Answer 7

Guava is a pretty neat library from Google:

Joiner joiner = Joiner.on(", ");
joiner.join(sList);

Answer 8

I prefer String.join(list) in Java 8

Answer 9

Have you seen this Coding Horror blog entry?

The Sad Tragedy of Micro-Optimization Theater

I am not shure whether or not it is "neater", but from a performance-standpoint it probably won't matter much.

Answer 10

ArrayList inherits its toString()-method from AbstractCollection, ie:

public String toString() {
    Iterator<E> i = iterator();
    if (! i.hasNext())
        return "[]";

    StringBuilder sb = new StringBuilder();
    sb.append('[');
    for (;;) {
        E e = i.next();
        sb.append(e == this ? "(this Collection)" : e);
        if (! i.hasNext())
            return sb.append(']').toString();
        sb.append(", ");
    }
}

Building the string yourself will be far more efficient.

---

If you really want to aggregate the strings beforehand in some sort of List, you should provide your own method to efficiently join them, e.g. like this:

static String join(Collection<?> items, String sep) {
    if(items.size() == 0)
        return "";

    String[] strings = new String[items.size()];
    int length = sep.length() * (items.size() - 1);

    int idx = 0;
    for(Object item : items) {
        String str = item.toString();
        strings[idx++] = str;
        length += str.length();
    }

    char[] chars = new char[length];
    int pos = 0;

    for(String str : strings) {
        str.getChars(0, str.length(), chars, pos);
        pos += str.length();

        if(pos < length) {
            sep.getChars(0, sep.length(), chars, pos);
            pos += sep.length();
        }
    }

    return new String(chars);
}

Answer 11

It seems to me that the StringBuilder will be quick and efficient.

The basic form would look something like this:

public static String concatStrings(List<String> strings)
{
    StringBuilder sb = new StringBuilder();
    for(String s: strings)
    {
        sb.append(s);
    }
    return sb.toString();       
}

If that's too simplistic (and it probably is), you can use a similar approach and add a separator like this:

    public static String concatStringsWSep(List<String> strings, String separator)
{
    StringBuilder sb = new StringBuilder();
    for(int i = 0; i < strings.size(); i++)
    {
        sb.append(strings.get(i));
        if(i < strings.size() - 1)
            sb.append(separator);
    }
    return sb.toString();               
}

I agree with the others who have responded to this question when they say that you should not rely on the toString() method of Java's ArrayList.

Answer 12

Rather than depending on ArrayList.toString() implementation, you could write a one-liner, if you are using java 8:

String result = sList.stream()
                     .reduce("", String::concat);

If you prefer using StringBuffer instead of String since String::concat has a runtime of O(n^2), you could convert every String to StringBuffer first.

StringBuffer result = sList.stream()
                           .map(StringBuffer::new)
                           .reduce(new StringBuffer(""), StringBuffer::append);

Answer 13

I somehow found this to be neater than using the StringBuilder/StringBuffer approach.

I guess it depends on what approach you took.

The AbstractCollection#toString() method simply iterates over all the elements and appends them to a StringBuilder. So your method may be saving a few lines of code but at the cost of extra String manipulation. Whether that tradeoff is a good one is up to you.

Answer 14

Next variation on Peter Lawrey's answer without initialization of a new string every loop turn

String concatList(List<String> sList, String separator)
{
    Iterator<String> iter = sList.iterator();
    StringBuilder sb = new StringBuilder();

    while (iter.hasNext())
    {
        sb.append(iter.next()).append( iter.hasNext() ? separator : "");
    }
    return sb.toString();
}

Answer 15

In java 8 you can also use a reducer, something like:

public static String join(List<String> strings, String joinStr) {
    return strings.stream().reduce("", (prev, cur) -> prev += (cur + joinStr));
}

Answer 16

Assuming it's faster to just move a pointer / set a byte to null (or however Java implements StringBuilder#setLength), rather than check a condition each time through the loop to see when to append the delimiter, you could use this method:

public static String Intersperse (Collection<?> collection, String delimiter)
{
    StringBuilder sb = new StringBuilder ();
    for (Object item : collection)
    {
        if (item == null) continue;
        sb.append (item).append (delimiter);
    }
    sb.setLength (sb.length () - delimiter.length ());
    return sb.toString ();
}

Answer 17

if you have json in your dependencies.you can use new JSONArray(list).toString()

Answer 18

Depending on the need for performance and amount of elements to be added, this might be an ok solution. If the amount of elements are high, the Arraylists reallocation of memory might be a bit slower than StringBuilder.

Answer 19

Using the Functional Java library, import these:

import static fj.pre.Monoid.stringMonoid;
import static fj.data.List.list;
import fj.data.List;

... then you can do this:

List<String> ss = list("foo", "bar", "baz");
String s = stringMonoid.join(ss, ", ");

Or, the generic way, if you don't have a list of Strings:

public static <A> String showList(List<A> l, Show<A> s) {
  return stringMonoid.join(l.map(s.showS_()), ", ");
}