Arithmatic operator overloading in c++

Question

#include<iostream>
using namespace std;
class money
{
    int rs;  
    int p; 

    public:

    void setdata (int x , int y) 

     {rs=x; p=y;}

    void show() 

   { cout  <<rs  <<"."  <<p; }  

    money operator += (int a)  {

    money temp;
    temp.rs=rs+a.rs;
    temp.p=p+a.p;   
    return (temp);  
    }
};



  int main() {

    money c1,c2;

    c1.setdata(8,2);

    c2=c1.operator+=(4);

    c2.show();

}

Can someone tell me why the operator += overloading doesn't work?

My desiring output is 12.2 but the output i got is 16.2 .

I am sending 4 as argument and i want this argument is added in r (ruppee) part

`+=` is supposed to modify `this` and return a reference to `this` — 463035818_is_not_an_ai, Sep 19 '18 at 10:03
Possible duplicate of [What are the basic rules and idioms for operator overloading?](https://stackoverflow.com/questions/4421706/what-are-the-basic-rules-and-idioms-for-operator-overloading) — 463035818_is_not_an_ai, Sep 19 '18 at 10:03
please make sure the code matches the problem you describe. See also [mcve] — 463035818_is_not_an_ai, Sep 19 '18 at 10:06
@user463035818 i just want to return temp into the c2 object — , Sep 19 '18 at 10:08
`temp.p=p;` you are not adding anything here. And if you fix that your operator is still doing the wrong thing. What you implemented is an `operator+` — 463035818_is_not_an_ai, Sep 19 '18 at 10:08
@user463035818 sir this is my assignment questions and its always throwing wrong output — , Sep 19 '18 at 10:11
@user463035818 13.5 + 1.5 = 15.00 what just i want to show sir — , Sep 19 '18 at 10:12
i still dont get it, but probably this ` temp.rs=rs+rs;` is not what you want but rather `temp.rs = rs + a.rs;`. Currently you dont use the `a` parameter at all — 463035818_is_not_an_ai, Sep 19 '18 at 10:13
@user463035818 i have just edited my code.. and it still throws a error about temp.rs = rs + a.rs; — , Sep 19 '18 at 10:15
why?? now it wont compile anymore. My mistake was to overlook that the parameter to the operator is an `int` not a `money`. If you want to add that `int` to your money then you need to add it... — 463035818_is_not_an_ai, Sep 19 '18 at 10:17
`rs` is an `int`, `a` is an `int`. How do you add two `int`s? — 463035818_is_not_an_ai, Sep 19 '18 at 10:19
@user463035818 affter adding it show 20.2 as an ouput it stills wrong. — , Sep 19 '18 at 10:20
hum this question is a train wreck. Here is the correct implementation: `money& operator+=(int a) { rs += a; return *this; }` and you use it as `c1 += 4;` — 463035818_is_not_an_ai, Sep 19 '18 at 10:22

score 0 · Answer 1 · answered Sep 19 '18 at 10:36

0

#include<iostream>
using namespace std;
class money
{
    int rs;  
    int p; 

    public:

    void setdata (int x , int y) 

     {rs=x; p=y;}

    void show() 

   { cout  <<rs  <<"."  <<p; }  

   money& operator+=(int a) 
   { rs += a; return *this; }
};



  int main() {

    money c1,c2;

    c1.setdata(4,2);

     c2=c1+=(4);               //c2=c1.operator+=(4);

    c2.show();

}

answered Sep 19 '18 at 10:36

`c2=c1+=(4);` is correct, but it completely misses the point of having a `operator+=` instead of a `operator+`. `operator+=` modifies the left hand side and its return can be assigned to `c2` but typically you dont. Just use `c1+=4; c1.show();` – 463035818_is_not_an_ai Sep 19 '18 at 11:12

score 0 · Answer 2 · answered Jul 22 '22 at 02:34

0

Try to use constructor correctly. For example:

#include <iostream>

using namespace std;

class Example
{
public:
    int x;
    Example(int a)
    {
        x=a;
    }
    Example operator+(Example obj)
    {
        Example ans(0);
        ans=x+obj.x;
        return ans;
    }
};

int main()
{
    Example a(10),b(20);
    Example ans=a+b;
    cout<<ans.x<<endl;
    return 0;
}

answered Jul 22 '22 at 02:34

Ahmed Aunek

11
3

Your answer could be improved with additional supporting information. Please [edit] to add further details, such as citations or documentation, so that others can confirm that your answer is correct. You can find more information on how to write good answers in the [help center](https://stackoverflow.com/help/how-to-answer). – Nol4635 Jul 25 '22 at 22:14

Arithmatic operator overloading in c++

2 Answers2