django/python: pass **kwargs

Question

I want to build a url. My function adds the word kwargs to the result, which it should not.

custom_redirect('mieteinheit', kwargs={"wohnungsgruppenname": form.cleaned_data["wohnungsgruppenname"]})

def custom_redirect(url_name, *args, **kwargs):
    #some code is passed
    "?%s" % urllib.parse.urlencode(kwargs)

This creates:

?kwargs=%7B%27wohnungsgruppenname%27%3A+%27ghs%27%7D

But it should create

?wohnungsgruppenname%3Dwohnungsgruppenname

Any ideas?

score 0 · Accepted Answer · answered Sep 19 '18 at 16:44

You missunderstood how keyword arguments are used.

Instead of calling your function like you do, try this instead:

custom_redirect(
    'mieteinheit', 
    wohnungsgruppenname=form.cleaned_data["wohnungsgruppenname"])

This way, the word 'wohnungsgruppenname' will become a key in the dict kwargs. The way you did it, it creates a nested dict, which is not what you nedd.

See this answer for a better explanation of how kwargs works.

django/python: pass **kwargs

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