What python code allows me to print out elements from a list that starts with a letter?

Question

Example: I created a list named months of the months of the year. How do I write a for loop that iterates over the elements of months and prints out each one that begins with letter ‘J’, one month per line.

Answer 1

In python you can iterate over a list using a for loop. You can then have a conditional statement that checks if the month begins with 'J'. Example:

months = ['January', 'February', 'March' 'June', 'October']
for month in months:
    if month[0] == 'J':
        print(month)

This results in

January
June

Answer 2

You can use .startswith()

[print(i) for i in months if (i.lower()).startswith('j')]

Or

months = ['January', 'July', 'Nov']
for i in months:
    i = i.lower()
    if (i.lower()).startswith('j'):
        print(i)

(xenial)vash@localhost:~/python/stack_overflow$ python3.7 example.py 
January
July

Answer 3

If you're looking for how to filter elements out based on their initial letter this should help: Checking whether a string starts with XXXX

months=["January","February","March","April","May","June","July","August","September","October","November","December"]
for m in months:
    if m.startswith('J'):
        print m

January
June
July

Answer 4

Iterate through each element and see if its a string. If it is, then check the first element.

yourList = ["January"]
checkLetter = "J"
for element in yourList:
    if isinstance(element,str):
        if element[0]== checkLetter:
            print(element)