main() wrapper to start wmain() program to compile it from commandline

Question

For example i have a program thats "main" function is defined as wmain.

int wmain( int argc, wchar_t *argv[] ) {
    wchar_t* lpModulePath = NULL;
    wchar_t* lpFunctionName = NULL;
    lpModulePath = argv[1];
    lpFunctionName = argv[2];
}

and of course uses wchar_t types. How can i write a function

int main( int argc, char *argv[] )

that converts the parameters passed as char to wchar_t and then calls wmain by itself?

Thank you

can you show some more code on what you want to achieve? – bashrc Sep 21 '18 at 11:25 — bashrc, Sep 21 '18 at 11:25
What do you mean by "some more"? A working program? – Jane dOE Sep 21 '18 at 11:27 — Jane dOE, Sep 21 '18 at 11:27

score 0 · Accepted Answer · answered Sep 21 '18 at 11:41

On Windows you can use GetCommandLineW() and CommandLineToArgvW():

int main(int argc, char* argv[])
{
    wchar_t** wargv = CommandLineToArgvW(GetCommandLineW(), &argc);
    int ret = wmain(argc, wargv);
    LocalFree(wargv);
    return ret;
}

On Linux I'm afraid you'd have to allocate the array and convert strings in loop.

main() wrapper to start wmain() program to compile it from commandline

1 Answers1