How to split a string into a list by digits?

Question

I have been looking for a way to split a string by digits, for instance:

st = "abc4ert"
from string import digits
st = st.split(digits)
--> st = ['abc','ert']

Is there a way to do that (without including the numbers in the list)?

I think the question is not a duplicate. Isn't the situation in the linked question different? — Sasha Tsukanov, Sep 21 '18 at 13:09

score 2 · Answer 1 · answered Sep 21 '18 at 12:30

2

Use Regex.

Ex:

import re

st = "abc4ert"
print(re.findall(r"[A-Za-z]+", st))

Output:

['abc', 'ert']

answered Sep 21 '18 at 12:30

Rakesh

7

It would be great if you explain this one liner `re.findall(r"[A-Za-z]+", st)`. It would be helpful to understand how it works for a larger audience reading your answer now and in the future – Sheldore Sep 21 '18 at 12:31
1

That's very basic regex literacy.`[...]` matches a single character which is one of the characters defined between the square brackets, and `A-Z` and `a-z` are character ranges whose semantics should be obvious. The `+` matches a sequence of one or more matches on the immediately preceding expression. – tripleee Sep 21 '18 at 12:33

score 2 · Answer 2 · answered Sep 21 '18 at 12:31

2

import re

st = "abc4ert"
st = re.split(r'\d+', st)
print(st)

Output:

['abc', 'ert']

answered Sep 21 '18 at 12:31

jdehesa

2 Answers2