Selenium: Fetch href from child class element

Question

I need to find all href inside class="mozaique"

My code:

gfd = driver.find_elements_by_xpath('/html[1]/body[1]/div[1]/div[4]/div[2]/div[1]/div[2]/div[1]/div[1]/div[2]/div[1]')

html:

Hope it will help https://stackoverflow.com/questions/47653309/beautifulsoup-select-all-href-in-some-element-with-specific-class — EMKAY, Sep 24 '18 at 14:51
Possible duplicate of [BeautifulSoup select all href in some element with specific class](https://stackoverflow.com/questions/47653309/beautifulsoup-select-all-href-in-some-element-with-specific-class) — shad0w_wa1k3r, Sep 24 '18 at 14:53

Kireeti Annamaraj · Accepted Answer · 2018-09-24T17:45:27.400

0

Below xpath should help you fetch all the links under tag:

<div> class='mozaique'</div>

Xpath:

//div[@class='mozaique']//a[contains(@href,'')]

You can print the href's using the below code snippet:

links = driver.find_elements_by_xpath('//div[@class='mozaique']//a[contains(@href,'')]')

for link in links:
    print(link.get_attribute("href"))

edited Sep 24 '18 at 17:45

answered Sep 24 '18 at 15:08

Kireeti Annamaraj

Hi thanks for reply. but It does not print the links :( – Sam Sagariya Sep 24 '18 at 16:50
@SamSagariya, I have updated the answer. Please check and let me know if it helps – Kireeti Annamaraj Sep 24 '18 at 17:45
@SamSagariyan can you try with this xpath?: `//div[@class='mozaique' and child::div[contains(@id,'video_')]]//*[contains(@href,'')]` – Kireeti Annamaraj Sep 25 '18 at 01:56
Unable to locate an element with the xpath expression!! The links are inside a frame – Sam Sagariya Sep 25 '18 at 02:05
So, did you try switching to the frame before actually trying to find elements? [switch to iframe](https://stackoverflow.com/questions/44834358/how-to-switch-to-an-iframe-through-selenium-and-python) – Kireeti Annamaraj Sep 25 '18 at 02:13
Bro ! Can you help!! https://stackoverflow.com/questions/52522884/beautifulsoup-get-whole-line-using-a-text – Sam Sagariya Sep 26 '18 at 17:13

Mono · Answer 2 · 2018-09-24T17:24:55.063

0

First, get your parent element:

parent = driver.find_element_by_class_name("mozaique")

Then get a list of all 'a' tags within your parent element.

a = parent.find_elements_by_tag_name("a")

Then run a loop to print the hrefs

for x in a:
    print(x.get_attribute("href"))

edited Sep 24 '18 at 17:24

answered Sep 24 '18 at 17:10

Mono

print(x.get_attribute("href")) This would give Element does not exist error. – amitnair92 Nov 20 '19 at 10:05

2 Answers2