Python 3, How to remove part of an element of a list if it contains a specific thing3

Question

I have a list of data that comes in the form of lists with numbers in them. as an intermediate step to making them all integers, I need to remove all the non-number parts within the element.

['jeff','69','420','80085\n']

how do I check to see if \n is in an element and how do I remove it if it is?

['jeff','69','420','80085']

Is the wanted output. I literally don't know how to start, I can turn the numbers into integers using loops and intermediate variable but trying to identify things within them is not something i know how to do.

But `'jeff'` is not a number either. Don't you want it removed? — blhsing, Sep 25 '18 at 06:07
Please show what you've tried based on your research into this task — roganjosh, Sep 25 '18 at 06:07
@Bollehenk, given that there is absolutely no code here, how is that a reasonable duplicate? — Stephen Rauch, Sep 25 '18 at 06:11
Not like del or pop because I don't wont to remove the whole element. just the stuff within them that is equal to /n — Alice D, Sep 25 '18 at 06:13

abhinsit · Accepted Answer · 2018-09-25T06:12:01.780

0

>>> input = ['jeff','69','420','80085\n']
>>> output = [x.replace('\n','') for x in input]
>>> output
['jeff', '69', '420', '80085']

edited Sep 25 '18 at 06:12

answered Sep 25 '18 at 06:10

abhinsit

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where did 80085 go speedy – vash_the_stampede Sep 25 '18 at 06:10
oh, i didn't even know replace was a thing. Thanks so much! – Alice D Sep 25 '18 at 06:13

Python 3, How to remove part of an element of a list if it contains a specific thing3

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