Extract exact URL's from string in php

Question

I need to extract the all url's from the string using php , I refered below url but not getting exact result I want. Reference url and my string are below,

$string = "hi new image one http://xxx/images/c4ca4238a0b923820dcc509a6f75849b208754572.jpgand two arehttp://yyy/images/c1f1a611c1147c4054c399c01f8bad76686484492.jpgend";
$regex = '#\bhttps?://[^,\s()<>]+(?:\([\w\d]+\)|([^,[:punct:]\s]|/))#';
preg_match_all($regex, $string, $matches);
echo "<pre>";
print_r($matches[0]);

am getting result are

Array
(
    [0] => http://xxx/images/c4ca4238a0b923820dcc509a6f75849b208754572.jpgand
)

It shows only one result , but in string 2url's are available, is it possible to get below result,

Array
    (
        [0] => http://xxx/images/c4ca4238a0b923820dcc509a6f75849b208754572.jpg
        [1] => http://yyy/images/c1f1a611c1147c4054c399c01f8bad76686484492.jpg
    )

How to remove appending text in front and end of url and filter exact url's from string ? Any help Appreciated

But the end of the url, they are what you have as input url ? — vieroli, Sep 25 '18 at 09:47
does this is the real string you want to parse? or just an example? the regex pattern is completely correct, the issue is in your string — hassan, Sep 25 '18 at 09:48
also, what about the end of the uri part? are you always matching against an image with the jpg extension? — hassan, Sep 25 '18 at 09:51
https://stackoverflow.com/questions/36564293/extract-urls-from-a-string-using-php?noredirect=1&lq=1 — Professor Abronsius, Sep 25 '18 at 10:10
Possible duplicate of [Extract URL's from a string using PHP](https://stackoverflow.com/questions/36564293/extract-urls-from-a-string-using-php) — Professor Abronsius, Sep 25 '18 at 10:10
@hassan , am not only matching with jpg, maybe its any type of image format — Thiyagarajan, Sep 25 '18 at 10:14
@RamRaider , am already added reference link , so read my question correctly — Thiyagarajan, Sep 25 '18 at 10:15
@Thiyagarajan If images url end with `and` & `end` you can use `@http://[^\s]+(?=and|end)@` — Mohammad, Sep 25 '18 at 10:23
@mohammad , If matching with any string means what we use instead of and|end? am using * but its wrong — Thiyagarajan, Sep 25 '18 at 10:30
@mohammad using '@http://[^\s]+.(jpg|png|gif|swf|jpeg)@' is resolved m issue — Thiyagarajan, Sep 25 '18 at 10:38

hassan · Answer 1 · 2018-09-25T10:13:22.973

The problem is in you are matching a link with a boundary of the http word

$regex = '#\bhttps?://[^,\s()<>]+(?:\([\w\d]+\)|([^,[:punct:]\s]|/))#';
//         ^^ note this

omitting the boundary will get the full list of urls in your string

$regex = '#https?://[^,\s()<>]+(?:\([\w\d]+\)|([^,[:punct:]\s]|/))#';

will output:

Array (
    [0] => http://xxx/images/c4ca4238a0b923820dcc509a6f75849b208754572.jpgend
    [1] => http://yyy/images/c1f1a611c1147c4054c399c01f8bad76686484492.jpgand
)

You SHOULD match against some fixed suffix in the end of the url.

I will assume that you want to match against jpg,jpeg,png images , so your pattern may look like:

$regex = '#https?://[^,\s()<>]+(?:\([\w\d]+\)|([^,[:punct:]\s]|/)\.(jpg|jpeg|png))#';

Live example: https://3v4l.org/WACo1

yeah great and simple one, +1 for answer – Thiyagarajan Sep 25 '18 at 10:11 — Thiyagarajan, Sep 25 '18 at 10:11

score 0 · Answer 2 · answered Sep 25 '18 at 09:52

You can make a for loop. With the size of the array $matches And then print the result.

<?php
$string = "hi new image one http://xxx/images/c4ca4238a0b923820dcc509a6f75849b208754572.jpgand two are http://yyy/images/c1f1a611c1147c4054c399c01f8bad76686484492.jpgend";
$regex = '#\bhttps?://[^,\s()<>]+(?:\([\w\d]+\)|([^,[:punct:]\s]|/))#';

preg_match_all($regex, $string, $matches);
echo "<pre>";

for($i=0;$i<sizeof($matches);$i++){
    print_r($matches[$i]); 
}

Try this, and let me know if it match your needs

it also give exact result , but hassan gives simple solution — Thiyagarajan, Sep 25 '18 at 10:18

score 0 · Answer 3 · answered Sep 25 '18 at 10:17

Here is the answer to your question

    $string = "hi new image one http://xxx/images/c4ca4238a0b923820dcc509a6f75849b208754572.jpg  and two are http://yyy/images/c1f1a611c1147c4054c399c01f8bad76686484492.jpg end";
    $strArray = explode(' ', $string);
    $newString = "";
    $url = array();
    foreach($strArray as $word)
    {
      if (substr($word, 0, 7) == "http://" || substr($word, 0, 8) == "https://")
      {
        $url[] = $word;
      } else {
        if ($newString != '')
          $newString .= ' ';
        $newString .= $word;
      }
    }

     print_r($url);

Extract exact URL's from string in php

3 Answers3