Separating a list in python into tuples

Question

I have a nested list where 2 lists are included in the main list. The 2nd list has no items lets say A = [[3,4,5,1,6,],[]]

I want to separate the 1st list into tuples in a way that it gives the following output: output >> (3,4),(4,5),(5,1),(1,6)

Can you please help me with this??

Please show what you have tried based on your research around this requirement — roganjosh, Sep 25 '18 at 12:30
How about a list comprehension `tups = [(lst[0][i], lst[0][i+1]) for i in range(len(lst[0])-1)]` — Sheldore, Sep 25 '18 at 12:33
@Bazingaa - It works perfectly. Thanks a lot for your support and I appreciate it very much. — , Sep 25 '18 at 12:42

score 0 · Accepted Answer · answered Sep 25 '18 at 12:34

0

Try this:

result = [(A[0][i],A[0][i+1]) for i in range(len(A[0])-1)]

output:

[(3, 4), (4, 5), (5, 1), (1, 6)]

answered Sep 25 '18 at 12:34

Taohidul Islam

Thanks a lot..... This is exactly what i wanted :D – Sep 25 '18 at 12:43
1

Welcome, if this answer helps you then you can accept the answer by pressing on the tick mark – Taohidul Islam Sep 25 '18 at 12:44
1

I accepted it and the tick is in green colour now – Sep 25 '18 at 12:51

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