I need to print out the vowels in horton in the order they appear using a for loop, this is what i have so far.
horton = "A person's a person, no matter how small."
vowels = "aeiouAEIOU"
for letters in horton:
if letters == vowels[0:9]:
print(letters)
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Replace if letters == vowels[0:9]: to if letters in vowels: will solve your problem.
Simple explanation: == will check whether the left element is identical to the right element, in your case, to the left of == is a single letter, while to the right is "aeiouAEIO" (yeah, there's a capital U missing as well) and they can't be identical in any case.
Full programme:
horton = "A person's a person, no matter how small."
vowels = "aeiouAEIOU"
for letters in horton:
if letters in vowels:
print(letters)
# A
# e
# o
# a
# e
# o
# o
# a
# e
# o
# a
One-liner:
print(''.join([i for i in horton if i.lower() in 'aeiou']))
Output:
Aeoaeooaeoa
If want in newlines:
print('\n'.join([i for i in horton if i.lower() in 'aeiou']))
Output:
A
e
o
a
e
o
o
a
e
o
a
Or regex:
import re
print(''.join(re.findall(r'[aeiou]',"mississippi")))
Output:
Aeoaeooaeoa
If newline:
import re
print('\n'.join(re.findall(r'[aeiou]',"mississippi")))
Output:
A
e
o
a
e
o
o
a
e
o
a
