Bash expand variable in an another variable

Question

I have the following variables

my_country_code="green"
x="country"

echo ${my_$x_code}
bash: ${my_$x_code}: bad substitution

echo should print green as output, but unable to find any technique which will give the correct output

`x=country; declare "my_${x}_code=green"; var="my_${x}_code"; echo "${!var}"` — Inian, Sep 27 '18 at 03:07

score 4 · Answer 1 · answered Sep 27 '18 at 03:03

4

my_x_code="my_${x}_code"
echo ${!my_x_code}

answered Sep 27 '18 at 03:03

Chris Dodd

Do keep in mind the note re: questions which "...have already been asked and answered many times before" in the "Answer Well-Asked Questions" section of [How to Answer](https://stackoverflow.com/help/how-to-answer) – Charles Duffy Sep 27 '18 at 03:26

1 Answers1