Just wondering, what is the difference between these initialization in classes in C++
first:
Complex (): real(0), imaginary(0) { }
second:
Complex() {
real = 0;
imaginary = 0;
}
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Anand Sharma
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3Difference is that second is not initialization but assignment – Slava Sep 27 '18 at 13:57
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You know, other than the last dupe, which may be slightly harder to find, simply searching for the text you put in bold produces the other duplicates. This is a poor attempt at research before asking. – StoryTeller - Unslander Monica Sep 27 '18 at 14:06
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i didn't knew the terminolgy "member initialization list". i thought it will be very hard to find the answer. – Anand Sharma Sep 27 '18 at 14:25
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In the first variant members are directly initialized with values (use when can). This is the only way to initialize const members. Constness has many useful side effects.
In the second variant members are first default-initialized (by the compiler generated code) then assigned values (use when cannot avoid, usually can).
bobah
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Not the down voter but I do know some people down vote answers on obvious dupes. – NathanOliver Sep 27 '18 at 14:05
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I guess the quality of this answer is not up there with those on the duplicates. – Bathsheba Sep 27 '18 at 14:09