Error while converting string into integer in java

Question

I am new to java and facing a problem while converting a string into an integer. my coding goes here-

import java.util.Scanner;
class Binary{
public static void main(String args[]){

    Scanner takeInput = new Scanner(System.in);
    System.out.println("Please Give Your Input ====> ");
    String binaryInput = takeInput.nextLine();
    System.out.println("Your Input Is ====> "+binaryInput);
    int lenGTH=binaryInput.length();

    for(int i = lenGTH ; i >= 0 ; i--){

        char pOsition = binaryInput.charAt(i);
        int convertIntoInteger = Int.parseInt(pOsition);
        int convertIntoDouble = Double.parseDouble(convertIntoInteger);
        int getPower = 0;
        getPower *= Math.pow(convertIntoDouble , 2);
        System.out.println("Power of " + i + " index " + getPower);
        }

    }
}

I am giving the screenshot for error in command prompt:enter image description here

If your code is indented properly, you are more likely to get people to try and read it. — khelwood, Sep 27 '18 at 16:59
`int i=lenGTH; i>=0; i--` - start at lenGTH - 1. Your String starts at index 0, and finishes at length-1. There is nothing worthwhile at index length. Also, this is a very unique casing you have there. Not saying CamelCase and snake_case are in danger, but nice anyway. — skandigraun, Sep 27 '18 at 16:59
`int convertIntoDouble=Double.parseDouble(convertIntoInteger);` ??? you are assigning `double` to `int` — The Scientific Method, Sep 27 '18 at 17:00
Oh yeah. It should be also `Integer.parseInt`, not Int.parseInt — skandigraun, Sep 27 '18 at 17:03
Also trying to parse a double from an integer, instead of from a string. — khelwood, Sep 27 '18 at 17:04
@khelwood i think convert a string into double will give u just another error, because it may not be logically right to convert a string, say, "1" into "1.00" — KAPIL SHARMA, Sep 27 '18 at 17:08
showing in command prompt: binary.java:18: error: incompatible types: char cannot be converted to String double convertIntoDouble=Double.parseDouble(pOsition); ^ Note: Some messages have been simplified; recompile with -Xdiags:verbose to get full output 1 error — KAPIL SHARMA, Sep 27 '18 at 17:19
Try it like `Double.parseDouble(binaryInput.substring(i, i+1))`. Maybe you will have to use `i-1` instead of one of the indices. — skandigraun, Sep 27 '18 at 17:27
@skandigraun, it worked thanx. valueOf() method worked too... The one more problem was taking i = lenGTH, instead of lenGTH-1. Thanks for your answer and i used valueOf() methd. — KAPIL SHARMA, Sep 27 '18 at 19:43

Abhay · Answer 1 · 2018-09-27T17:22:37.970

0

There is no such class Int in java.

Try this:

int convertIntoInteger=Integer.parseInt(String.valueOf(p0sition));

Integer class is used to parse data in int.

edited Sep 27 '18 at 17:22

answered Sep 27 '18 at 17:04

Abhay

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i used valueOf() as Integer.valueOf() and it worked! Thanks bro – KAPIL SHARMA Sep 27 '18 at 19:48

Error while converting string into integer in java

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