How to sort a list in python based on internal list?

Question

I have a list as follow:

list1 = [['10', 'John', 'python'], ['1', 'Sara', 'java'], ['3','Tom', 'C']]

and as sorted result I expect following outpt:

3 Tom C
1 Sara Java
10 John python

in fact I want to sort it base on second parameter in internal list. This code does not work:

sort1 = sorted(list1, key=lambda x: x[0][1])

Mehrdad Pedramfar · Accepted Answer · 2018-10-01T11:48:30.610

1

try this:

sort1 = sorted(list1, key=lambda x: x[1])

that [1] will be enough because it will iterate through the list and in each iteration x will be the inner list.

edited Oct 01 '18 at 11:48

answered Oct 01 '18 at 11:47

Mehrdad Pedramfar

1

Please Add explanation. – Arpit Svt Oct 01 '18 at 11:47
It just needs to add **reverse=True** to the end to receive expected answer. – Babak Memar Oct 01 '18 at 12:25

1 Answers1