Poco::Logger print int8_t value

Asked Oct 01 '18 at 21:25

Active Oct 01 '18 at 21:25

Viewed 649 times

I am trying to print int8_t value with Poco::Logger in this way:

using myint8_t = signed char;
myint8_t var;
var = 10;
logger().information("%c", var);
logger().information("%d", var);
logger().information("%i", var);

But as output have error which tells me that argument does not match the format specifier:

2018-10-02 00:12:40.627 [Information] [ERRFMT]
2018-10-02 00:12:40.627 [Information] [ERRFMT]
2018-10-02 00:12:40.627 [Information] [ERRFMT]

Where is my mistake and how to print signed char value with Poco::Logger? Thanks.

asked Oct 01 '18 at 21:25

definename

1

Related: https://stackoverflow.com/questions/19562103/uint8-t-cant-be-printed-with-cout/19562163#19562163 – πάντα ῥεῖ Oct 01 '18 at 21:27
Totally unrelated: the `_t` suffix is reserved by the POSIX standard. Use with caution on POSIX compliant systems. – user4581301 Oct 01 '18 at 21:27
@πάνταῥεῖ I my case I use `signed char`. In example above `unsigned char` is used. – definename Oct 02 '18 at 08:29
1

Try to use `logger().information("%?i", var);` – rafix07 Oct 02 '18 at 09:27
It works with `%?i` but what modifiers `?` means? According to the documentation it is: `? argument is any signed or unsigned int, short, long, or 64-bit integer (d, i, o, x, X).` Could you please explain me more deeper. – definename Oct 02 '18 at 09:50
@definename The related point is the cast, if you want to output a number. – πάντα ῥεῖ Oct 02 '18 at 10:49
Poco uses a type safe format class but allows for any int cast via the `?` modifier. – Okkenator Mar 13 '20 at 13:06
See [format](https://pocoproject.org/docs/Poco.html#14526) – Okkenator Mar 13 '20 at 13:39

Poco::Logger print int8_t value

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