Scrolling to bottom of RecyclerView need to some delay then apply

Question

I have a RecyclerView which contains messages item. I want to scroll to the bottom of layout when the user has pressed a button (like chat application). I have tried this piece of code but it does not work.I need this task done after a few millisecond.Because new message add to adapter in the asynchronous call retrofit.

 imgSend.setOnClickListener(new View.OnClickListener() {
        @Override
        public void onClick(View v) {
            if(edtMessage.getText().length()>0) {
                sentUserMessage();
                edtMessage.setText("");
                //I try this line or next line.None of them doesn't work
                linearLayoutManager.scrollToPositionWithOffset(messages.size(),0);
                recyclerView.scrollToPosition(messages.size());
            }
        }
    });

You need to use `recyclerView.scrollToPosition(messages.size()-1);` — AskNilesh, Oct 02 '18 at 10:00
In this approach, RecyclerView scroll to two the last item Not last item — maryam, Oct 02 '18 at 10:11

score 1 · Answer 1 · answered Oct 02 '18 at 07:21

1

try this

recyclerView.post(new Runnable() {
    @Override
    public void run() {
        // Call smooth scroll  
        recyclerView.smoothScrollToPosition(adapter.getItemCount().length());                                 
    }
});

answered Oct 02 '18 at 07:21

Kevin Kurien

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It work. but I need this code done after a few millisecond.Because new message add to adapter in the asynchronous call retrofit. – maryam Oct 02 '18 at 07:37
@sarina you can add a progressDialog to show the user new data is uploading and scroll to the bottom when dialog.dismiss is called – Kevin Kurien Oct 02 '18 at 08:45
This solution isn't suitable for me. Because my app is chat application and it isn't logical to show a progressDialog to user. User write a message and the activity should go to bottom where new massage is placed. – maryam Oct 02 '18 at 09:14

Scrolling to bottom of RecyclerView need to some delay then apply

1 Answers1