Get a string after a special character Python RegEx

Question

How can i get a string after a special character?

For example I want to get the string after / in

my_string = "Python/RegEx"

Output to be : RegEx

I tried :

h = []
a = [ 'Python1/RegEx1' , 'Python2/RegEx2', 'Python3/RegEx3']

for i in a: 
    h.append(re.findall(r'/(\w+)', i))
print(h)

But the output is : [['RegEx1'], ['RegEx2'], ['RegEx3']]

I need : ['RegEx1', 'RegEx2', 'RegEx3']

Thanks in advance

RegEx beginner

Assuming `h` is defined somewhere (maybe `h = []`?), changing `.append(...)` to `.extend(...)` should work. — jedwards, Oct 04 '18 at 18:08

score 0 · Answer 1 · answered Oct 04 '18 at 18:09

0

Loop through the list of lists you get with another for loop.

For example:

a = [ 'Python1/RegEx1' , 'Python2/RegEx2', 'Python3/RegEx3']

for i in a: 
    h.append(re.findall(r'/(\w+)', i))

for x in h:
    print(x)

answered Oct 04 '18 at 18:09

ech0

512
4
14

score 0 · Answer 2 · answered Oct 04 '18 at 18:09

For something like this where you only have one / per item, you could use map to .split('/') each item and then take .split('/')[1] from each item to create the list

a = [ 'Python1/RegEx1' , 'Python2/RegEx2', 'Python3/RegEx3']
a = list(map(lambda x: x.split('/')[1], a))
# ['RegEx1', 'RegEx2', 'RegEx3']

Or list comprehension

a = [i.split('/')[1] for i in a]

Expanded :

l = []
for i in a:
    i = i.split('/')
    l.append(i[1])

score 0 · Accepted Answer · answered Oct 04 '18 at 18:10

0

You may use [0] in front of findall:

>>> h = []
>>> for i in a:
...     res = re.findall(r'/(\w+)', i)
...     if res:
...           h.append(res[0])
...
>>> print (h)
['RegEx1', 'RegEx2', 'RegEx3']

answered Oct 04 '18 at 18:10

anubhava

761,203
64
569
643

2

This helps. Thanks @anubhava – Ebin Davis Oct 04 '18 at 18:19
how to strip if we have more than once special character on the same string? `my_string = "/Python/RegEx"` output to be: `RegEx` – Ebin Davis Oct 05 '18 at 08:16
Change regex to `r'/(\w+)$'` – anubhava Oct 05 '18 at 10:28

score 0 · Answer 4 · answered Oct 04 '18 at 18:11

0

Using .extend():

for i in a: 
    h.extend(re.findall(r'/(\w+)', i))

Using += (just another way to call .extend):

for i in a: 
    h += re.findall(r'/(\w+)', i)

Using unpacking:

for i in a: 
    h.append(*re.findall(r'/(\w+)', i))

answered Oct 04 '18 at 18:11

jedwards

29,432
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Get a string after a special character Python RegEx

4 Answers4