Check if a Duplicated list present out of multiple lists

Question

I have the following Lists: I need to check if it has duplicates we assume (['f', 't'] = ['t', 'f']) (order of elements in the list does not matter) and hence this should return 'duplicate' as it has both the lists

['f', 't']
['f', 'r']
['t', 'f']
['f', 'u']
['b', 't']
['b', 'r']
['b', 'l']
['b', 'u']
['r', 't']
['r', 'u']
['l', 't']
['l', 'u']

and I did try to run an iteration to check if any duplicate lists but it fails as each element is compared to itself in the iteration one time. Any leads to the same will be appreciated

Do you just want "yes" or "no" there are duplicates? Or do you want to know what are the duplicates? — SethMMorton, Oct 10 '18 at 05:25
Possible duplicate of [Check if two unordered lists are equal](https://stackoverflow.com/questions/9623114/check-if-two-unordered-lists-are-equal) — Mateen Ulhaq, Oct 10 '18 at 05:27

score 0 · Accepted Answer · answered Oct 10 '18 at 05:31

Try this:

duplicate_list = [['f', 't'],
['f', 'r'],
['t', 'f'],
['f', 'u'],
['b', 't'],
['b', 'r'],
['b', 'l'],
['b', 'u'],
['r', 't'],
['r', 'u'],
['l', 't'],
['l', 'u']]

seen = set()
for el in duplicate_list:
    el = frozenset(el)
    if el in seen:
        print("Duplicate")
        break
    seen.add(el)

Check if a Duplicated list present out of multiple lists

1 Answers1