I try to sort a dictionary by value using
sort = sorted(the_dict.items(), key = lambda x : x[1])
but this returns a list of tuples.
How can I return a dict that has the keys sorted in descending value order?
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What version of Python are you using? – jedwards Oct 12 '18 at 03:24
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Python 3 version – Dawn17 Oct 12 '18 at 03:25
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3.what? Since 3.6 you can do something like `x = dict(sorted(the_dict.items(), key = lambda x : x[1]))` – jedwards Oct 12 '18 at 03:26
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check this [link](https://www.saltycrane.com/blog/2007/09/how-to-sort-python-dictionary-by-keys/) – user3713719 Oct 12 '18 at 03:30
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It does not really sort by the value – Dawn17 Oct 12 '18 at 03:36
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Possible duplicate of [sort dict by value python](https://stackoverflow.com/questions/16772071/sort-dict-by-value-python) – stovfl Oct 12 '18 at 05:56
1 Answers
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Very close, you need a dict() constructor to make it a dictionary, note that operator.itemgetter(1) could replace lambda
d = {'vash': 1, 'the': 5, 'stampede': 12}
new_d = dict(sorted(d.items(), key=lambda x: x[1], reverse = True))
# {'stampede': 12, 'the': 5, 'vash': 1}
vash_the_stampede
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