How to convert []byte to *bytes.Buffer

Question

I am trying to decode a gob output that I am sending through another fasthttp endpoint and receiving an error Fasthttp endpoint(encode []string through gob) ----> Fasthttp endpoint( receive and decode)

buffer := &bytes.Buffer{}
buffer  = ctx.PostBody()
backToStringSlice := []string{}  
gob.NewDecoder(buffer).Decode(&backToStringSlice)

I am getting error: ctx.PostBody() (type []byte) as type *bytes.Buffer in assignment

how do I convert []byte to *bytes.Buffer.

Any help is appreciated.

`res := []byte{}; bytes.NewBuffer(res)` – nilsocket Oct 12 '18 at 07:59 — nilsocket, Oct 12 '18 at 07:59

score 16 · Accepted Answer · edited Jul 07 '20 at 11:12

16

NewBuffer will do what you want

package main

import (
    "fmt"
    "bytes"
)

func main() {
        foo:=[]byte{65,66,67}
        z:=bytes.NewBuffer(foo)
    fmt.Println("Hello, playground", foo, z)
}

edited Jul 07 '20 at 11:12

Yves M.

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answered Oct 12 '18 at 09:19

Vorsprung

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wow...i feel ashamed i had to google this, so simple, thank you – Keith E. Truesdell Nov 21 '22 at 21:20

How to convert []byte to *bytes.Buffer

1 Answers1