In the abc.h file I have a class:
class ABC
{
public:
template <typename... Args>
ABC(Args... args);
protected:
template <typename Type, typename... Args>
void processArguments(Type &argument, Args... args);
template <typename Type>
void processArguments(Type &argument);
template <typename Type>
void doSomethingWithTheArgument(Type &argument);
};
Then, I created abc.cpp with the following:
template <typename... Args>
ABC::ABC(Args... args)
{
processArguments(args...);
}
template <typename Type, typename... Args>
void ABC::processArguments(Type &argument, Args... args)
{
doSomethingWithTheArgument(argument);
processArguments(args...);
}
template <typename Type>
void ABC::processArguments(Type &argument)
{
doSomething(argument);
}
template <typename Type>
void ABC::doSomethingWithTheArgument(Type &argument)
{
std::cout << argument << std::endl;
}
And just some test.cpp:
int main()
{
ABC abc(1, 2, 3, "somehing", 2 + 5);
return 0;
}
And then I wanted to build it with the following command line:
g++ --std=c++11 abc.cpp test.cpp
And then bang!
/tmp/ccflWDpf.o: In function `main':
test.cpp:(.text+0x3b): undefined reference to `ABC::ABC<int, int, int, char const*, int>(int, int, int, char const*, int)'
collect2: error: ld returned 1 exit status
And when I put whole code in a single xyz.cpp file the code compiles fine. Does it tells that implementation of variadic templates cannot be provided in different translation unit?
