How to remove an item from a list in python with substring match

Question

I have got a list l1 = ['00001MMYYYSSSS', '00002YYSSMMYNNN', '00003FFMMNNNSS'] and another list l2 = ['00001', '00003']. I need to remove the items at index 0 and 2 in the list l1 as it contains the string given in l2. How do I go about doing this?

I have tried the solutions mentioned [here]Is there a simple way to delete a list element by value? and [here]Python: subset elements in one list based on substring in another list, retain only one element per substring but they return an empty list. Thank you!

score 2 · Accepted Answer · answered Oct 13 '18 at 20:34

2

This should work:

l1 = ['00001MMYYYSSSS', '00002YYSSMMYNNN', '00003FFMMNNNSS']

l2 = ['00001', '00003']

l_result = [x for x in l1 if not any(l in x for l in l2)]  # ['00002YYSSMMYNNN']

answered Oct 13 '18 at 20:34

Antoine Zambelli

724
7
19

CiroRa · Answer 2 · 2018-10-13T20:58:27.320

0

# Hello World program i

l1 = ['00001MMYYYSSSS', '00002YYSSMMYNNN', '00003FFMMNNNSS'] 
l2 = ['00001', '00003']
L3=[]

for el in l2:

  for el1 in l1:
    if el in el1:
     L3.append(el1)
for l3 in L3:
    l1.remove(l3)
print l1

edited Oct 13 '18 at 20:58

answered Oct 13 '18 at 20:33

CiroRa

492
3
13

I tried it but print l3, prints out an empty list. In fact l3.append(el1) is marked as unreachable code. – Navaneeth Oct 13 '18 at 20:45
Try this one, I test ed it – CiroRa Oct 13 '18 at 20:59

How to remove an item from a list in python with substring match

2 Answers2