Starting programs with arguments

Question

How can I start a program in the following way?

"C:\Users\Administrator\Downloads\exe1.exe" 13\10\2018 00:00:00 "C:\Program Files (x86)\Folder\exe2.exe"

I tried this way, but it did not work and an exception was thrown

Process.Start("\"C:\\Users\\Administrator\\Downloads\\exe1.exe\" 13\\10\\2018 00:00:00 \"C:\\Program Files (x86)\\Folder\\exe2.exe\"")

Can you show how you would execute the program from the command prompt with the right parameters? — Lasse V. Karlsen, Oct 13 '18 at 21:21

score 0 · Answer 1 · answered Oct 13 '18 at 21:33

0

answered Oct 13 '18 at 21:33

kaffekopp

score 0 · Answer 2 · answered Oct 13 '18 at 21:46

Two Things are wrong here:

You can't include parameters in the Process.Start(filename) method. You need to use Process.Start(filename, parameters) method.
Don't escape the double quotes, in fact its' a normal string, so skip those double quotes.

You method can be called like this:

Process.Start("C:\\Users\\Administrator\\Downloads\\exe1.exe",  "C:\\Program Files (x86)\\Folder\\exe2.exe");

2 Answers2