PHP Notice:what is the pro

Question

I've been getting this error. Any fix??

PHP Notice: Undefined offset: 1 in line 402

if ($argv[1] == '--cover')
{
    $Modules = new Modules;
    $Modules->cover();
    die();
}

The line is if ($argv[1] == '--cover')

Try to print_r($argv) to see what does the result – Osama Oct 13 '18 at 21:33 — Osama, Oct 13 '18 at 21:33

score 1 · Answer 1 · answered Oct 13 '18 at 21:40

1

An offset is undefined if it doesn't exist in the array. Try this:

if(isset($argv[1]) && $argv[1] == '--cover'){
$Modules = new Modules;
$Modules->cover();
die();

answered Oct 13 '18 at 21:40

RGe

1,181
1
10
19

score 0 · Answer 2 · answered Oct 13 '18 at 21:39

0

This error means that the $argv[1] is undefined or null. Make sure this variable is properly assign or have a value before making a condition.

using print_r($argv); before making a condition will help you if the variable have a value or not.

answered Oct 13 '18 at 21:39

Ed Ward

26
3

PHP Notice:what is the pro

2 Answers2