Getting key from dictionary

Question

I have a this type dictionary

   a= {(93, 184): b'\x01*\x00P\xd2\xac2\xdf5\xfeT\xaa\xa7\beb\x80\x10\d01\x1d\xf9=\x00\x00\x01\x01\x08\nLy\x16\xd4\xa68.\xc4'}

Its key (93,184) changes every time.

I want to get my key for example a[x][x]=(93,184)

How can I do this? I am using Python 3.6

`list(a.keys())[0]`, with `a` defined as in your question, returns `(93, 184)` (at least in python 3, can't remember if python 2 had a different syntax) — GPhilo, Oct 15 '18 at 10:42
sometimes it can be (90,102) or (80,120) so i want to get dict's key. — CKocar, Oct 15 '18 at 10:46
@CKocar tested it on IDLE 3.6.5, and it worked great. that's weird. — lucas_7_94, Oct 15 '18 at 10:51
`list(a.keys())` should work and return dictionary key as a list. — Reddysekhar Gaduputi, Oct 15 '18 at 10:59
You want to **change** a `dict key`, thats not possible. You have to **insert** new key, **copy** value from old key, **delete** old key — stovfl, Oct 15 '18 at 12:17
Possible duplicate of [How to return dictionary keys as a list in Python?](https://stackoverflow.com/questions/16819222/how-to-return-dictionary-keys-as-a-list-in-python) — jkhadka, Oct 15 '18 at 13:19

score 0 · Accepted Answer · answered Oct 15 '18 at 13:16

0

Although your question is not very clear,

Here is how you could get your keys into a list.

a= {(93, 184): b'\x01*\x00P\xd2\xac2........'}
b=list(a.keys())
print(b)

Hope it helps.

answered Oct 15 '18 at 13:16

Kshitij Dhyani

1 Answers1