Making a list from items at n position

Question

I'm trying to make a nested list using data from other lists. I want to make a list where the n items from other lists are at n position in the outer list.

red = [1, 2, 3]
green = [4, 5, 6]
blue = [7, 8, 9]

What I tried doing:

index= []
[index.append(n)for n in (red, green, blue)]   
print(index)

What I got:

[[1, 2, 3], [4, 5, 6], [7, 8, 9]]

What I want:

[[1, 4, 7], [2, 5, 8], [3, 6, 9]]

Or use numpy- for example: `np.array([red, green, blue]).T.tolist()` — pault, Oct 15 '18 at 17:11

score 3 · Accepted Answer · answered Oct 15 '18 at 17:10

3

What you really need is this:

list(map(list, zip(red, green, blue)))

which is equivalent to:

[list(l) for l in zip(red, green, blue)]

which returns:

[[1, 4, 7], [2, 5, 8], [3, 6, 9]]

answered Oct 15 '18 at 17:10

Rocky Li

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Making a list from items at n position

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