Why is destructuring assignment used here? and what exactly is it doing?

Asked Oct 15 '18 at 18:38

Active Oct 15 '18 at 18:55

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In the Node JS Child Process documentation, the following line is given in an example:

const { spawn } = require('child_process');

Why is destructuring assignment used here? and what exactly is it doing? Is this implying that require('child_process') returns an object with multiple elements, and 'spawn' is the first? (I thought objects' elements were not in any guaranteed order?)

asked Oct 15 '18 at 18:38

Ryan Griggs

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the `require()` returns an object, but `spawn` is property of that object, not necessarily the first. The property *name* is "spawn". – Pointy Oct 15 '18 at 18:39
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It's like `const x = require("child_process"); const spawn = x.spawn;` – Pointy Oct 15 '18 at 18:40
Got it. Thanks for clarifying. – Ryan Griggs Oct 15 '18 at 18:40

Why is destructuring assignment used here? and what exactly is it doing?

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