How protected access modifier works in Java?

Asked Oct 16 '18 at 09:16

Active Oct 16 '18 at 09:16

Viewed 50 times

I have these classes:

package com.a;

public class A {
  protected String v="A";
}
----------------------------------------------------------------------------- 
package com.b;

import com.a.A;

public class B extends A {
public static void main(String[] args) {
    System.out.println(new A().v);
  }
}

But new A().v doesn't compile.Why? I thought subclass has access to parent's variables even though it's in separate package.

asked Oct 16 '18 at 09:16

Mukhamedali Zhadigerov

3

Because you aren't doing `new B().v` – Mad Physicist Oct 16 '18 at 09:18
2

@Oleksandr. Interesting that the dupe even uses a similar attempt at a horizontal separator. Nice find. – Mad Physicist Oct 16 '18 at 09:20
1

@Oleksandr Ok. I found answer to my question.Thanks – Mukhamedali Zhadigerov Oct 16 '18 at 09:21

How protected access modifier works in Java?

0 Answers0