c++ initialization of struct with std::list included

Question

I have the following question.

Check the below block of code, it initializes my members of my structure correctly.

typedef struct
{
    int var00;
    int var01;
}struct_;

int main()
{


    struct_ my_struct;
    memset(&my_struct,'\0',sizeof(struct_));
    return 0;
}

My new structure now(see below), includes also an std::list. What I have to do now, to keep the memset command in the code?

typedef struct
{
    int var00;
    int var01;
    std::list<int> my_list
}struct_list_included;

int main()
{


    struct_list_included my_struct;
    memset(&my_struct,'\0',sizeof(struct_list_included));
    return 0;
}

Why not simply provide a constructor? Also, those typedefs are not needed in C++. — , Oct 16 '18 at 15:08
If you are coming from a C background and are learning C++ I suggest you get yourself a [good C++ book](http://stackoverflow.com/questions/388242/the-definitive-c-book-guide-and-list). Your code has a lot of C-ism's in it that are unnecessary as C++ has built in mechanics to do these things. — NathanOliver, Oct 16 '18 at 15:15

score 1 · Answer 1 · answered Oct 16 '18 at 15:08

1

std::list is not a POD type, so I don't think you can do this via memset().

answered Oct 16 '18 at 15:08

gsamaras

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c++ initialization of struct with std::list included

1 Answers1