Access array outside for loop

Question

I want to access array variable outside the loop. but its returning null. below is sample code.

var result = [];
for (var i=0; i < 10; i++) {
     result.push[i];
}

What exactly are you trying to do? `result.push[i]` does not do anything. — Jerodev, Oct 17 '18 at 10:03
@DarkBee because a function is an object in JS. `array.push[2] = 'foo'` creates a property `2` on the `push` method with value `foo`. — nicholaswmin, Oct 17 '18 at 11:38
actually want achieve below code `var args ={},fileObject = []; for (var i in files) { base64.encode('/opt/zipoutput/' + files[i], function (err, base64String) { convertval = base64String; var dataObj = { "actions": [ { "file_path": files[i] }] }; fileObject.push(dataObj); }); } console.log("fileObject111-----",fileObject);` — Jay, Oct 17 '18 at 12:01
@Jaykumar - Please [edit](https://stackoverflow.com/posts/52852179/edit) your question to provide more updates/clarifications — DarkBee, Oct 17 '18 at 13:54

score 3 · Answer 1 · answered Oct 17 '18 at 10:03

3

The syntex of push method is push() not push[].

var result = [];
for (var i=0; i < 10; i++) {
    result.push(i);
}
console.log(result);

answered Oct 17 '18 at 10:03

Sudhir Ojha

actually want achieve below code `var args ={},fileObject = []; for (var i in files) { base64.encode('/opt/zipoutput/' + files[i], function (err, base64String) { convertval = base64String; var dataObj = { "actions": [ { "file_path": files[i] }] }; fileObject.push(dataObj); }); } console.log("fileObject111-----",fileObject);` – Jay Oct 17 '18 at 11:37

Mamun · Answer 2 · 2018-10-18T04:11:41.477

1

push is a method implemented on array. The basic syntax of invoking or calling a function is to specify parenthesis () after the function name.

The push() method adds one or more elements to the end of an array and returns the new length of the array.

var result = [];
for (var i=0; i < 10; i++) {
     result.push(i);
}
console.log(result);

edited Oct 18 '18 at 04:11

answered Oct 17 '18 at 10:05

Mamun

Neeraj Dwivedi · Answer 3 · 2018-10-17T10:17:43.800

0

Please use the below code:

var result = [];      
for (var i=0; i < 10; i++) {      
    result.push(i);      
}

edited Oct 17 '18 at 10:17

answered Oct 17 '18 at 10:04

Neeraj Dwivedi

score 0 · Answer 4 · answered Oct 17 '18 at 14:44

0

You can do that like this also.

var result = [];
    for (var i=0; i < 10; i++) {
         result[i]=i;
    }

If you want to use push then use like this result.push(i)

answered Oct 17 '18 at 14:44

4 Answers4