I need to find within a stored procedure which values match a wanted total following valex's solution recursive query in SQL Server
The following works pretty well assuming the CTE anchor recordset is very small
CREATE TABLE #t ([id] INT, [num] FLOAT);
DECLARE @wanted FLOAT = 100000
INSERT INTO #t ([id], [num])
VALUES (1, 17000), (2, 33000), (3, 53000), (4, 47000), (5, 10000),
(6, 53000), (7, 7000), (8, 10000), (9, 20000), (10, 5000),
(11, 40000), (12, 30000), (13, 10000), (14, 8000), (15, 8000),
(16, 10000), (17, 74000)
/* when you add more records the query becomes too slow, remove this comment
to test*/
/*,(18,10000),(19,78000),(20,10000),(21,10000),(22,80000),(23,19000),
(24,8000),(25,5000),(26,10000),(27,4000),(28,46000),(29,48000),(30,20000),
(31,10000),(32,25000),(33,10000),(34,13000),(35,16000),(36,10000),
(37,5000), 38,5000),(39,30000),(40,15000),(41,10000)*/
;
CREATE NONCLUSTERED INDEX [idx_id] ON #t ([id]);
WITH CTE AS
(
SELECT
id, num AS CSum,
CAST(id AS VARCHAR(MAX)) AS path
FROM
#t
WHERE num <= @wanted
UNION ALL
SELECT
#t.id, #t.num + CTE.CSum AS CSum,
CTE.path + ',' + CAST(#t.id AS VARCHAR(MAX)) AS path
FROM
#T
INNER JOIN
CTE ON #T.num + CTE.CSum <= @wanted AND CTE.id < #T.id
WHERE
#T.num + CTE.CSum <= @wanted
)
SELECT TOP 1 Path
FROM CTE
WHERE CTE.CSum = @wanted
ORDER BY id
DROP TABLE #t
It will return 3,4 which are the first 2 rows whose [num] values gives the @wanted total.
This works reasonably fast when there are just a few records in the temp table #t but when you remove the comment and all remaining records (from id 17 to id 41) the query just takes forever because the CTE grows exponentially.
Is there a way to speed up the code? i just need the first matching total (the list anchor dataset is ordered so a result like 3,4 is better than 8,20,22)