how would I add a counter to this

Question

I want to add a counter to this code so every time the word ligma is printed it counts the number of times ligma was printed on the screen

import winsound
import time
from threading import Thread

def play_sound():
    for _ in range(10):
        winsound.PlaySound("dank", winsound.SND_ALIAS)
        time.sleep(2.5)

thread = Thread(target=play_sound)
thread.start()

while True:
    print ('ligma')
    time.sleep(1.5)

Also check out https://stackoverflow.com/q/7186336/1076479 – Gil Hamilton Oct 17 '18 at 20:54 — Gil Hamilton, Oct 17 '18 at 20:54

score 1 · Answer 1 · answered Oct 17 '18 at 20:52

1

count = 0
while True:
    print ('ligma')
    count += 1
    time.sleep(1.5)

answered Oct 17 '18 at 20:52

mindfolded

216
1
8

1

Was it playing before? This shouldn't stop it from playing. – mindfolded Oct 17 '18 at 20:55
I probably should have clarified that I wanted it to count that on screen – Oct 17 '18 at 21:02
Just print the count with the ligma print. `print('ligma - {}'.format(count))` output: `ligma - 1, ligma - 2, etc.` – mindfolded Oct 17 '18 at 21:04

how would I add a counter to this

1 Answers1