How to use the module in Julia v0.7

Question

I have the following set up: module xxxxx at the top of my file named xxxxx.jl

I go to do the following:

include("modules/xxxxx/xxxxx.jl") using xxxxx

I get the following error:

ERROR: LoadError: ArgumentError: Package xxxxx not found in current path: - Run Pkg.add("xxxxx") to install the xxxxx package.

Any suggestions? I don't have this error on Julia v0.6 only on v0.7!

Thanks!

score 5 · Accepted Answer · answered Oct 17 '18 at 22:14

5

Write

using .xxxxx

By using include function the module is loaded as a submodule of a current module. E.g. if you included it in global scope then you can also write

using Main.xxxxx

But the syntax I gave at the top would work no matter if you are in Main module or you include a submodule in another module defined by you.

answered Oct 17 '18 at 22:14

1

Ok, I think that fixed the issue. I am trying to call a function in one of the files I do – logankilpatrick Oct 17 '18 at 22:50
1

using xxxxx; include("/Users/logankilpatrick/.julia/packages/xxxxx/7IWZq/src/simNomadic.jl"); sim_nomadic() – logankilpatrick Oct 17 '18 at 22:50
I do this in the Julia command line version. It says that ERROR: UndefVarError: sim_nomadic not defined Stacktrace: [1] top-level scope at none:0 – logankilpatrick Oct 17 '18 at 22:51
Any suggestions? – logankilpatrick Oct 17 '18 at 22:54
I looked it up as doing MyModule.nameOfFunction() works! – logankilpatrick Oct 17 '18 at 23:32
https://stackoverflow.com/questions/51824403/how-to-import-modules-and-functions-from-a-file-in-a-specific-directory-in-julia – logankilpatrick Oct 17 '18 at 23:33
you can also export `nameOfFunction` from module `xxxxx` and then it will be visible after `using .xxxxx`. – Bogumił Kamiński Oct 18 '18 at 05:51

1 Answers1