Python Falsk name

Asked Oct 18 '18 at 03:05

Active Oct 18 '18 at 03:08

Viewed 32 times

In a default Flask app, PyCharm generates the following code:

from flask import Flask
app = Flask(__name__)

@app.route('/')
def hello_world():
    return 'Hello, World!'

if __name__ == '__main__':
    app.run()

In almost all of the tutorials I'm following (socketio, right now), It wants me to add initialization code within the if statement (like so):

if __name__ == '__main__':
    app = socketio.Middleware(sio, app)
    eventlet.wsgi.server(eventlet.listen(('', 8000)), app)

QUESTION

__name__ seems to always equal app Which means __name__ does not equal __main__ and therefore will not enter this if statement. What exactly is the purpose of this if statement? Is it PyCharm specific or maybe some way to start the application in production? If so, how does production automatically set the __name__ to __main__?

Trying to figure out where these variables come from so I can figure out proper placement of code (ie: socketio).

Reference: https://python-socketio.readthedocs.io/en/latest/

edited Oct 18 '18 at 03:08

eyllanesc

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asked Oct 18 '18 at 03:05

mwilson

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`app = Flask(__name__)` does not mean that `__name__` equals `app`. For one thing, there's a `Flask` in the middle. – jwodder Oct 18 '18 at 03:07
I used `print(__name__)` and it printed `app` – mwilson Oct 18 '18 at 03:07
2

You may want to read [What does `if __name__ == “__main__”:` do?](https://stackoverflow.com/q/419163/744178) – jwodder Oct 18 '18 at 03:08
@jwodder Thanks for the link. That answer my question! – mwilson Oct 18 '18 at 03:09

Python Falsk __name__

0 Answers0

Python Falsk name