EDIT: This is for my Java class. In class, my prof did a similar problem and the answer he's expecting will most definitely be a number.
EDIT: (left to right), (right to left) is the associativity of operator
int a = 3;
int b = a++ + ++a + a * 2 + ++a;
//So b = 24 & a = 6
I am uncertain to why this is the answer. My reasoning is:
int a = 3;
int b = a++ + ++a + a * 2 + ++a;
(3) + (5) + (5 * 2) + (6)
//a is 3, increments to 4 but stays as 3 [a++]
//a is now 4 but increments to 5 [++a]
//Since I'm evaluating left to right [a * 2] is [5 * 2]. This is because a holds the value 5.
//a is 6 [++a]
Is my logic correct? Does the compiler evaluate it like this? I understand that the order of precedence in terms of this question, where var is an arbitrary variable, goes like:
"post" --------------> var++ & var-- (left to right)
"pre" ---------------> ++var & --var (right to left)
"multiplication" ----> * var & var* (left to right)
What is the general rule for stuff like this if instead we were taking the power, dividing, or modulating a variable in an expression like this?
