ifelse function in R

Question

I am using the formula below to calculate a vector but when executed, it returns a matrix; here is the code:

FdeValue <- ifelse(fde.4$ResourceId == 2196 |fde.4$FullYearForecast == 'Yes' | !is.na(fde.2$8), 0, fde.4$Value)

Any idea why will it do that ?

Please make your example reproducible! Read https://stackoverflow.com/questions/5963269/how-to-make-a-great-r-reproducible-example — jogo, Oct 19 '18 at 13:50
unfortunately , i cant upload the data. Problem i see is that the heading/column name of the resulting vector is the column name used in the third condition, which is really weird — Fahadakbar, Oct 19 '18 at 13:57
At least show us the `str` of the data then. Also, a non-standard column name (here, `8`) shouldn't be able to be used with the `$` operator; is this code actually running? — Aaron left Stack Overflow, Oct 19 '18 at 14:01

score 0 · Accepted Answer · edited Oct 19 '18 at 16:50

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In my opinion it is because of the dim of your logical input. Ifelse returns a value of the same dim as your logical input.
Try this:

c(fde.4$ResourceId ,fde.4$FullYearForecast, is.na(fde.2$8))==c(2196,'Yes', FALSE)

edited Oct 19 '18 at 16:50

jogo

answered Oct 19 '18 at 13:58

T. Ciffréo

Try this: c(fde.4$ResourceId ,fde.4$FullYearForecast, is.na(fde.2$8))==c(2196,'Yes', FALSE) – T. Ciffréo Oct 19 '18 at 13:59
awesome, it worked, but i still do not understand why it happened , i am using same formula for another vector and that is working fine, why would ifelse return the same dimension as logical input ? – Fahadakbar Oct 19 '18 at 14:43
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Ifelse checks every single element of your logical vector and do not see it as an unique assumption. Therefore for every 'TRUE' or 'FALSE' it returns the output you indicate. – T. Ciffréo Oct 19 '18 at 15:18
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It is applied element by element so if you apply an operation on a vector of length n or a matrix of dim n*m you get an output of respectively length n or dim n*m – T. Ciffréo Oct 19 '18 at 15:19

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