Python not responding correctly to user input

Question

I have been making a code to try to respond to the user input as a joke to send to a friend. But everytime I input a passcode it prints 'Access Denied.' And I'm using Spyder to code it.

Here is the code:

import time
print "Please enter your name to acess file."
userName=raw_input();
print "Searching Database..."
time.sleep(0.5)
print "Searching Database.."
time.sleep(0.5)
print "Searching Database."
time.sleep(0.5)
print "Searching Database.."
time.sleep(0.5)
print "Hello {} please input passcode.".format(userName)
passCode=raw_input();
if passCode != 0000:
    print 'Access Denied'
else:
    print 'Access Granted'

Try looking at `passCode` to see what it actually contains. You might also want to try looking at its `type()` (i.e. by running `type(passCode)` and comparing it to `type(0000)`. — ChrisGPT was on strike, Oct 19 '18 at 15:23
`if passCode != 0000:`? or `if passCode != 0:` or `if passCode != '0000':` — depperm, Oct 19 '18 at 15:23

Petar Velev · Answer 1 · 2018-10-19T15:32:43.543

3

Your comparison is wrong. You are comparing the string pass with the 0000 which is a number.

if passCode != '0000':
    print 'Access Denied'
else:
    print 'Access Granted'

0x5453

raw_input returns an object of type str, which should not be compared to an object of type int.

edited Oct 19 '18 at 15:32

answered Oct 19 '18 at 15:27

Petar Velev

2,305
12
24

To elaborate, `raw_input` returns an object of type `str`, which should not be compared to an object of type `int`. – 0x5453 Oct 19 '18 at 15:29

score 1 · Answer 2 · answered Oct 19 '18 at 15:30

if int(passCode) != 0000:  # notice the integer wrapper
    print 'Access Denied'
else:
    print 'Access Granted'

Make sure you are comparing the right types. You can also do this:

if passCode != '0000':
    print 'Access Denied'
else:
    print 'Access Granted'

Python not responding correctly to user input

2 Answers2