how do i get the contents from " value="" "

Question

This is the code :

#!/bin/bash
head=`curl -D -s "http://example.com/" | grep "j_id__v_0:javax.faces.ViewState:2"`
echo $head

and the output in terminal :

            </script>
            <input type="hidden" name="GlobalFooter_SUBMIT" value="1" />
            <input type="hidden" name="javax.faces.ViewState" id="j_id__v_0:javax.faces.ViewState:2" value="V7wZDq4cDizFPZ0i52hQGUD25XgWp5NJC+hCql33eTTwC2hm" autocomplete="off" />
        </form>
    </div>
</div>

How do I print the contents of the value?

https://stackoverflow.com/questions/1732348/regex-match-open-tags-except-xhtml-self-contained-tags/1732454#1732454 , but maybe also just `... | grep -o 'value="\K[^"+)"'` , or if your `grep` doesn't understand that, `perl -lne 'print $1 if /value="([^"]+)"/'` — Corion, Oct 20 '18 at 19:40

score 0 · Answer 1 · answered Oct 21 '18 at 18:55

Add a sed after the grep to keep only the value:

#!/bin/bash

head=$(curl -D -s "http://example.com/" | grep "j_id__v_0:javax.faces.ViewState:2" | sed 's/.*\svalue="\(\S*\)"\s.*/\1/')
echo $head

Couple points:

use the $() syntax to assign commands results to a variable. The backtick syntax, altough it works, is legacy syntax.
\s: whitespace
\S: anything but whitespace. I used that since .* is greedy and would include everything after value="SOMETHING" autocomplete="off

how do i get the contents from " value="" "

1 Answers1