Javascript extract value

Question

I'm using weather-js with this code :

weather.find({search: 'San Francisco, CA', degreeType: 'F'}, function(err, result) {
  if(err) console.log(err);

  console.log(JSON.stringify(result, null, 2));
});

But I don't know how I could extract the result value from this

"I don't know how I could extract the result value" -- I don't know what you mean — Dexygen, Oct 21 '18 at 18:21
I want a var that contain "result" outside of this, the console.log will be removed. — Wirex, Oct 21 '18 at 18:24

score 0 · Answer 1 · answered Oct 21 '18 at 18:28

The result should be like this:

[
  {
    "location": {
      "name": "San Francisco, CA",
      "lat": "37.777",
      "long": "-122.42",
      "timezone": "-7",
      "alert": "",
      "degreetype": "F",
      "imagerelativeurl": "http://blob.weather.microsoft.com/static/weather4/en-us/"
    },
    "current": {
      "temperature": "70",
      "skycode": "32",
      "skytext": "Sunny",
      "date": "2017-03-14",
      "observationtime": "13:15:00",
      "observationpoint": "San Francisco, California",
      "feelslike": "70",
      "humidity": "59",
      "winddisplay": "3 mph West",
      "day": "Tuesday",
      "shortday": "Tue",
      "windspeed": "3 mph",
      "imageUrl": "http://blob.weather.microsoft.com/static/weather4/en-us/law/32.gif"
    },
    "forecast": [
      {
        "low": "52",
        "high": "69",
        "skycodeday": "31",
        "skytextday": "Clear",
        "date": "2017-03-13",
        "day": "Monday",
        "shortday": "Mon",
        "precip": ""
      },
      {
        "low": "52",
        "high": "70",
        "skycodeday": "34",
        "skytextday": "Mostly Sunny",
        "date": "2017-03-14",
        "day": "Tuesday",
        "shortday": "Tue",
        "precip": "10"
      },
      {
        "low": "56",
        "high": "63",
        "skycodeday": "26",
        "skytextday": "Cloudy",
        "date": "2017-03-15",
        "day": "Wednesday",
        "shortday": "Wed",
        "precip": "20"
      },
      {
        "low": "50",
        "high": "64",
        "skycodeday": "28",
        "skytextday": "Mostly Cloudy",
        "date": "2017-03-16",
        "day": "Thursday",
        "shortday": "Thu",
        "precip": "10"
      },
      {
        "low": "53",
        "high": "67",
        "skycodeday": "32",
        "skytextday": "Sunny",
        "date": "2017-03-17",
        "day": "Friday",
        "shortday": "Fri",
        "precip": "10"
      }
    ]
  }
]

In the result, there are many useful information:

latitude & longitude of the location
current temperature of the location
forecast information for next four days

All those information exist in the result JSON that you can parse and use it. Consider that the result is an JSON array with only one element in this case. for example you can log current temperature like this:

console.log(result[0].current.temperature)

score 0 · Answer 2 · answered Oct 21 '18 at 18:30

Declare a variable and write the result into this variable, if no error occured:

var res = null;
weather.find({search: 'San Francisco, CA', degreeType: 'F'}, function(err, result) {
  if(err) {
    console.log(err);
  } else {
    res = result;
  }

  console.log(JSON.stringify(result, null, 2));
});

Javascript extract value

2 Answers2