Convert only time part in android from string to time

Question

I need to convert a time stamp that currently is in string format "08.00" to a valid time in java so I later can compare time. How do I convert this string to time?

Answer 1

Something like this

        DateFormat sdf = new SimpleDateFormat("hh:mm");
        Date date = sdf.parse(time);            

Answer 2

Instead of using the Date and/or SimpleDateFormat classes, perhaps consider LocalTime

String time = "08:00";
LocalTime lt = LocalTime.parse(time);
System.out.println(lt);

Output:

08:00

And can compare to other times easily with LocalTime::isBefore() or LocalTime::isAfter()

Example

Answer 3

Try below code,

String time = "08.00"; 
try {
    DateFormat sdfInput = new SimpleDateFormat("hh.mm");
    Date date = sdfInput.parse(time);

    DateFormat sdfOutput = new SimpleDateFormat("hh:mm");
    Log.e( "Time: ", sdfOutput.format(date));
} catch (Exception e) {
    e.printStackTrace();
}

Output -> Time: 08:00

Answer 4

The easiest way to do so is with a SimplDateFormatter:

DateFormat sdf = new SimpleDateFormat("hh:mm")

Then you can call Date date = sdf.parse(*your time string*)

Now you have your time as a valid Date object.

Answer 5

I have timeformat like this hhmmss="151918" so you can use any format instead of hhmmss according to your current time format like "hh.mm" or hh:mm:ss etc and you can call this method form any where you needed.

 fun convertTimeFormat(time:String):String{
        var formattedTime=""
        try {
            val inputFormat: DateFormat = SimpleDateFormat("hhmmss")
            val timeObj = inputFormat.parse(time)
            Log.d("timeObj",""+timeObj)
            formattedTime=SimpleDateFormat("hh:mm aa").format(timeObj)
        } catch (e: ParseException) {
            e.printStackTrace()
        }
        return formattedTime
    }